Marathon PrizesDate: 01/10/98 at 22:15:49 From: Thomas L Subject: Permutations Ten runners are competing in a marathon. In how many ways can the first and second prizes be awarded? Also, There are 7 possible commercials to be used in 3 time slots. How many possible arrangements are there? Thanks for your help. Date: 01/11/98 at 08:50:07 From: Doctor Anthony Subject: Re: Permutations There are 10 ways that the first prize could be awarded, and now with 9 to choose from, there are 9 ways that the second prize could be awarded. So the total number of ways that the two prizes could be awarded is 10 x 9 = 90 ways. For the second question we must choose 3 from the 7 to go into the time slots. We could choose the first in 7 ways, then the second in 6 ways and finally the third in 5 ways. This would give 7 x 6 x 5 = 210 ways. However the order in this question does not matter, and for any group of 3 commercials, we could rearrange them amongst themselves in 3 x 2 x 1 = 6 ways. So the group of 3 commercials could be chosen in 210/6 = 35 ways. In the first question we were dealing with permutations where the order matters, while in the second question we were dealing with combinations where order does not matter. There are formulae that can be used in each situation. nPr is the number of permutations of r things that can be made from n different things. 10 P 2 = 10 x 9 = 90 = answer to first question. nCr is number of combinations of r things that can be made from n different things 7 x 6 x 5 210 7 C 3 = --------- = ----- = 35 = answer to second question. 1 x 2 x 3 6 -Doctor Anthony, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/