Free FallDate: 10/16/97 at 09:01:22 From: Randy De Souza Subject: Free Fall A ball with a mass of 0.5kg is dropped from a height of 190cm. The ball is in flight for 5 sec, with gravity acting on it. We can assume that the ball will hit the ground and bounce back to half the initial height. Given this information determine: a) How long will it take for the ball to come to rest? b) How fast will the ball be traveling on the intial drop? c) Why does the ball change change colour from red to blue? How do you do this problem? Date: 10/16/97 at 15:13:18 From: Doctor Rob Subject: Re: Free Fall The acceleration of gravity is constant, regardless of the mass. Call it g cm/sec^2. Then the acceleration is g, the velocity is v = g*t + v0, and the height is s = g*t^2/2 + v0*t + s0. Up until the first bounce, since the ball was "dropped," we assume that v0 = 0, and we are given that s0 = 190 cm. If it hits the ground after t1 = 5 seconds, we have an equation 0 = g*5^2/2 + 190, which allows us to determine g = -380/25 = -76/5 = -15.2. Obviously this is on a small planet, since at the surface of Earth, g = -980 cm/sec^2. Between the first and second bounce, we have s0 = 0, so s = -7.6*(t-5)^2 + v0*(t-5), so s = 0 when t = t1 or t1 + v0/7.6, and the maximum height will occur halfway in between, at t = 5 + v0/15.2, so 95 = -7.6*(v0/15.2)^2 + v0^2/15.2, which allows us to solve for v0 = Sqrt[95*30.4] = 38*Sqrt[2] = 53.74, so the time of the second bounce is t = t1 + 5*Sqrt[2] = 12.07. Let t2 = 5*Sqrt[2], the time taken for the second bounce. Between the second and third bounce, a similar analysis tells us that the time is t3 = 5. Then t4 = 5/Sqrt[2]. In fact one can show that t(n+1)/t(n) = 1/Sqrt[2] for all n. The time until the ball comes to rest is T = 5 + Sum t(n), where the sum is over all n > 1. Then the sum is a geometric progression, so you can add it up, getting T = 5 + 5*Sqrt[2]/(1 - 1/Sqrt[2]) = 15 + 10*Sqrt[2], or about 29.142 seconds. Maximum absolute speed on the initial drop is 15.2*5 = 76 cm/sec. The ball must turn color because of the heating caused by the conversion of potential and kinetic energy into heat, which happens because the ball doesn't rebound to its full height from which it was dropped. The initial energy of the ball is all potential, which you can calculate. Why red and blue, I have no idea. -Doctor Rob, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
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