Coefficient of Friction
Date: 10/17/97 at 06:05:01 From: Stuart Cliff Subject: Coefficient of Friction From experiments carried out I have found that the formula "F=xR" Where F = Frictional force x = coefficient of friction R = Reactional force Does not hold true; that is, the angle of the slope "#" (and therefore x) needs to be decreased when the mass of the object is increased - yet the angle "#" should remain constant. For the life of me, I am unable to figure out why (pure mathematics is my strength). Any ideas? Thanks!
Date: 10/22/97 at 11:24:59 From: Doctor Mark Subject: Re: Coefficient of Friction Hi, Stuart You don't say whether you are talking about static or kinetic friction, so I can't really figure out what your difficulty is. However, I can explain what the deal is with these two kinds of friction. Static and kinetic friction both result from the "stickiness" between two objects. The origin of friction is not at all simple, and is the subject of the field of Rheology. That is, one does not generally derive the coefficient of friction, one measures it experimentally. Kinetic friction is the easier of the two to understand. If one object is sliding along another, then the frictional force acting on one of the objects is given by F_k = mu_k times N, where the "_" denotes a subscript, mu is the coefficient of friction, and N is the "normal force" exerted by the other object on the object in question (actually, the component of this force perpendicular (hence the word "normal") to the interface between the two objects. Generally, one finds the normal force by using Newton's second law, F = ma (as a vector equation), and from that you can find the frictional force. Note that the kinetic frictional force always has a direction opposite to that of the velocity of the object. Static friction is more complicated. The static frictional force is the force of one object on another when the two objects are not sliding over one another. As a result, this is given not by an equality (an equation), but by an INequality, namely, that F_s is (less than or equal to) mu_s times the normal force. Generally, you find the static frictional force by (as always) applying F = ma, and demanding that the net force be ZERO (of course, because if it's static friction, the object is not sliding over the other one, and so the velocity is zero, and constant, so a is zero, and so the net force is zero). The direction of the static frictional force is always opposite to the direction in which the object would move, given the other forces, if there were no friction. Generally, what you do is find the normal force by demanding that the sum of the components of the forces on the object perpendicular to the boundary between the two objects is zero. You then find the static frictional force by demanding that the sum of the components of the forces on the object parallel to the boundary between the two objects is zero. You then use the inequality to find some condition for the object to stay at rest with respect to the other object. For instance, if it is a block sitting on a plane inclined at an angle B to the horizontal, then the Normal force is given by N = mg cos B. The static frictional force will be given by F_s = mg sin B. Both of these results are obtained by applying F = ma to the object; since it is at rest and staying at rest, a = 0. Using the inequality mentioned above, you find that the angle B must be such that tanB is less than or equal to mu_s in order for the block to stay at rest on the incline. This means that if the angle is bigger than arctan(mu_s), the block will start moving. At that time, kinetic friction will take over, and you have to redo the problem. Of course, this is one way of measuring the coefficient of static friction: put the block on the plane, start increasing the angle, then find the angle A at which the block starts to move. The coefficient of static friction is given by tan A. Generally, the coefficient of static friction is larger than that of kinetic friction, as is obvious if you have ever tried to push something across a floor - it is harder to *get* the thing moving than it is to *keep* it moving (if you think about it, how could that *not* be true?!), and since the normal force has not changed, the coefficient of static friction must be greater than that of kinetic friction. Depending on the constitution of the materials which are in contact, it is quite possible that the coefficient of friction could in fact depend on the mass of the object in question, since very dense materials would deform the surface they are in contact with, and that would increase the ratio of the frictional force to the mass (or normal force), i.e., the coefficient of friction. But for "hard" materials, that shouldn't be a very large effect. It probably does make a difference for materials which deform easily, such as the tires on a car. Having said all of this, I don't know if I have really answered your question, so please feel free to write back to me if you feel I have not. -Doctor Mark, The Math Forum Check out our web site! http://mathforum.org/dr.math/
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