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### Gravity

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Date: 05/21/99 at 11:38:31
From: Husni
Subject: Gravity

Newton's second law of motion states that F = ma, which means that the
force in Newtons needed to move an object of m kg with an acceleration
of a metres/second^2 equals mass of object * acceleration of object.
But why does any free-falling object fall at the rate of 9.8 metres/
second^2 despite its mass?

Thanks.
```

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Date: 05/21/99 at 16:05:34
From: Doctor Rick
Subject: Re: Gravity

Hello, Husni, welcome to Ask Dr. Math.

You have noticed the principle of the equality of inertial mass and
gravitational mass. Inertial mass is the "m" in Newton's second law,

F = ma

Inertial mass determines how much acceleration is caused by some
force. Gravitational mass is the "m" in Newton's law of gravitation,

F = -GMm/r^2

Gravitational mass determines how much force gravity exerts on an
object. We can find the acceleration due to gravity by substituting
F = ma in the law of gravity.

ma = -GMm/r^2

Because the inertial mass of any object is identical to its
gravitational mass, the m's cancel and we have

a = -GM/r^2

G is a universal constant. With M being the mass of the earth and r
its radius, the expression on the right comes out to 9.8 m/s^2.

Apart from experiment, there would have been no reason to assume that
the two kinds of mass would be the same, making gravitational
acceleration constant. People had a right to be surprised at the
results of Galileo's experiments on the Tower of Pisa or wherever.

In fact, this amazing coincidence, which most people never notice, led
to Einstein's theory of general relativity. In this theory, it turns
out that gravity is not a force after all, but the effect of "bending
of space-time." In other words, gravity is a "fictitious force" akin
to "centrifugal force" and the Coriolis "force." Like them, it is very
convenient to think of gravity as a force, but your observation gives
us reason to believe that it isn't really.

If you are acquainted with these fictitious forces, I could say more
about how gravity works. But I'd better stop now. This could get very
complicated very fast.

- Doctor Rick, The Math Forum
http://mathforum.org/dr.math/
```
Associated Topics:
High School Physics/Chemistry

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