Executive Committee Vote
Date: 01/21/97 at 21:56:03 From: Keith Cooke Subject: Probability and Statistics? 124 Delegates attend an annual convention at which a new 13-member executive committee will be elected from a list of 26 candidates. Each of the delegates must vote for 10 candidates (i.e must place an X next to at least 10 names on the list of 26). The question posed is: What is the lowest number of votes a candidate could get and be elected? I'm not sure whether this is a combinatorial, statistical, or impossible question. Under worst (or best) case scenario, I guess you could be elected with just one vote, but the question then becomes, what is the probability of that happening? I think that a number of practical assumptions would have to be made (e.g., everyone doesn't vote for the same ten candidates - random lists, no spoiled ballots, etc.) in order to figure this out.
Date: 01/26/97 at 22:36:18 From: Doctor Mitteldorf Subject: Re: Probability and Statistics? Dear Keith, It seems to me that the "worst case" from the point of view of democracy would be if there were 10 candidates who were very popular, so that everyone voted for the same 10, and then there would be three more slots on the executive committee for which no candidates had any votes at all. You're right, that if this scenario "almost" obtained, it would be possible for all the votes but one to be concentrated in the top 12 candidates, so that the 13th prevailed with just one vote. To calculate the probability of this happening, you need some extra assumptions about human behavior. A very unrealistic assumption, but one that makes for an interesting and challenging statistics problem, would be to assume that every vote is random - that each delegate is equally likely to cast a vote for each candidate. Then there's a complicated combinatorial problem: how many ways can the votes be distributed so that there's a candidate who gets elected with only one vote? (The total number of ways the votes are distributed should go in the denominator, but that's relatively easy to compute.) If I had to answer this question for some practical purpose, I might decide that the combinatorial problem is too difficult, and I would use a "Monte Carlo simulation." I would program a computer to act like 124 voters selecting 10 candidates from a list of 26. The computer could make random selections, and tally up the votes in a tiny fraction of a second, then repeat the entire election several million times, noticing how many of the times resulted in this skewed result where someone gets elected by one vote. I'd go off and have lunch, and when I got back, the computer would give me an estimate of the probability that this might happen - under the very unrealistic assumption that each delegate is equally likely to cast a vote for each candidate. If we knew more about the voting behavior of real people in the situation, we could make the Monte Carlo simulation more realistic. (For example, we could say that everyone who votes for candidate A has an 80 percent chance of also voting for B, but only a 10 percent chance of voting for Z.) I can't tell if this is a practical problem for which you're seeking practical guidance, or an abstract mathematical amusement. If it's the latter, you might want to try formulating the problem in the way that makes it most interesting to think about. Try smaller numbers, and try counting the possible distributions of votes, and see it a formula suggests itself that extends to the larger numbers. But if it's a practical answer you're after, the Monte Carlo simulation is the way to go. -Doctor Mitteldorf, The Math Forum Check out our web site! http://mathforum.org/
Search the Dr. Math Library:
Ask Dr. MathTM
© 1994-2013 The Math Forum