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Roulette Questions

Date: 01/26/98 at 22:49:35
From: Humberto Castaneda
Subject: Probability/Statistics and gambling

Roulette Questions:

1. What is a safer bet: to bet on a number, or to bet on color?

2. Which bet maximizes your wins: betting on numbers, or betting on 

Thank You.

Date: 01/27/98 at 20:32:13
From: Doctor Bill
Subject: Re: Probability/Statistics and gambling


As to the question about the safety of betting, you're always going to 
lose in the long run, so no bet is "safe." As for which is the "better 
bet," it turns out they are about the same.

If we are assuming you are playing roulette in America (in Europe the 
roulette wheel is different) then there are 36 numbers, half red and 
half black, and also a 0 and a 00, both green. (In Europe there is not 
a 00.) The payoff for a bet on a number is 35-1 (notice that if it 
were a "fair" game the payoff would be 38-1,because there are 38 
different numbers, but that's how the house makes its money), and the 
payoff for red or black is 1-1 (notice here again the game is not 
quite fair since you will lose more often than you win because of the 
two green numbers, but you are paid off as if you win and lose an 
equal number of times).

In statistics and probability there is something called "mathematical 
expectation," which is the AVERAGE amount you will expect to win on 
any given play, if you play for a LONG time. (If the expectation is 
negative you "win" a negative amount, or in other words you expect to 
lose each time you play.) To find the expectation for a game you 
multiply each payoff times the probability of getting that payoff, and 
then add all of those numbers together. That total then is your 
EXPECTION. You probably won't win (or lose) that particular amount on 
any given play, but if you play for a long time you can "expect" to 
win that amount, on the average, each time you play. 

If we now look at the roulette game, suppose you bet $1 on the number 
5 each time you play. What are the payoffs? You can either win $35 or 
lose $1. The probability that you win $35 is 1/38 (only one winning 
number out of the total of 38). The probability that you lose $1 (that 
is you "win" $-1) is 37/38 (37 losing numbers out of the total of 38). 
To find the expectation of this game do the following calculation:  
35(1/38)-1(37/38). What do you get here? If it is positive you win and 
if it is negative you lose.

Suppose you bet $1 on RED each time you play. Here the payoffs are 
that you win $1 or lose $1. The probability of winning is 18/38 and 
the probability of losing is 20/38. (Do you see where these 
probabilities come from?) To find the expectation do the calculation:  

Notice that both of the calculations above came out negative, that is, 
you're going to lose in the long run. In these two cases I think they 
both came out the same, so it doesn't matter which way you bet your 
money, you're going to lose it at the same rate. If they had come out 
different, then the better bet would have been the bet with the 
highest expectation.

-Doctor Bill,  The Math Forum
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Associated Topics:
High School Probability

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