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Poisson Distributions with Conditional Probability
Date: 07/22/99 at 21:26:47
From: Kathleen
Subject: Statistics: Poisson distribution/conditional probability
Hello,
The question I'm trying to figure out is:
Let X be Poisson(2) and independent of Y which is Poisson(3) and let
W = X+Y. Find the distribution of X conditional on W = 10.
I have figured out that the sum of two independent random variables,
which have Poisson distribution, also has a Poisson distribution,
specifically of Poisson(a_1+a_2) where a_1, a_2 are the parameters of
the two independent random variables.
Thus, I know W will have distribution Poisson(5). I also know what the
probability functions look like for X being Poisson(2) and W being
Poisson(5).
Now I think (I could be wrong) that in order to find the distribution
of X conditional on W = 10 I want to figure out P(X|W=10).
Now using the conditional probability definition you have
P(X|W=10) = P(X,W=10)
---------
P(W=10)
I can easily figure out P(W=10) but my problem is that I don't know
how to figure out P(X,W=10). What is this intersection equal to? Could
you help please?
Thank you very much,
Kathleen
Date: 07/23/99 at 15:44:51
From: Doctor Anthony
Subject: Re: Statistics: Poisson distribution/conditional probability
P(X=1)* P(Y=9) 2*e^(-2) * 3^9/9! * e^(-3)
P(X=1|W=10) = -------------- = --------------------------
P(W=10) 5^10/10! * e^(-5)
2 * 3^9/9!
= ----------
5^10/10!
2 * 10 * 3^9
= ------------
5^10
393660
= -------
9765625
= 0.04031
and the other probabilities can be found in the same way. The maximum
value that X can take, given that W = 10, is of course 10.
- Doctor Anthony, The Math Forum
http://mathforum.org/dr.math/
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