Drexel dragonThe Math ForumDonate to the Math Forum

Ask Dr. Math - Questions and Answers from our Archives
_____________________________________________
Associated Topics || Dr. Math Home || Search Dr. Math
_____________________________________________

Johnny Carson's Birthday Problem


Date: 04/03/2002 at 20:51:48
From: Murad
Subject: Birthday problem

Johnny Carson had a guest on the Tonight Show who told him that the 
probability of two people in a group of 50 or more having their 
birthday on the same day was very high. Mr. Carson experimented with 
this on his show, choosing a guest at random to give his birthday, 
after which he asked that any other guest with the same birthday let 
it be known. the response was negative, and so he tried again with no 
luck then either. I was curious as to why this did not work.

Thank you,
Murad


Date: 04/03/2002 at 21:22:59
From: Doctor Ian
Subject: Re: Birthday problem

Hi Murad,

Here is the reasoning behind the probability. 

Assume there are two people. The probability that the second person
does NOT have the same birthday as the first is 364/365, or 0.997. 
(Do you see why?) 

Add a third person. The probability that the third person does NOT 
have the same birthday as either of the others is 363/365. So the
probability that none of the people have the same birthday is
(364/365) * (363/365), or 0.991.   

If you keep adding people, when you get to the 22nd person, the
probability that NONE of them have the same birthday is slightly less 
than 0.5. That means that the probability that AT LEAST TWO of them 
share a birthday is slightly greater than 0.5.

But that's NOT what Carson was testing. He picked a couple of people 
at random, and no one else shared THEIR birthdays.  This isn't to say 
that there weren't two or more people who shared a birthday that he 
didn't pick.  

What he should have done, to test the calculation, was to have 
everyone in the audience write his birthday on a slip of paper and 
pass the slips forward. Then he could have looked through them to see 
if there were two slips with the same date. In a room with 50 people, 
the chances of finding two such slips are quite good (although 
certainly not 100%). 

It would be very unlikely, but suppose that there were 50 people in 
the audience: one born on January 1, another on January 2, and 
everyone else on January 3. If Carson picks the first two guys, gets 
their birthdays, and asks for matches, he's not going to find any. But 
does that mean that there aren't any matches out there? Obviously not!

Probability can be a tricky subject, and very slight changes in the 
description of a situation ('there are two people out there who have 
the same birthday' versus 'there is another person out there with the 
same birthday as anyone I pick') can cause very large changes in the 
associated probabilities.  

Also, note that probabilities only tell you what is _likely_ to 
happen, not what _will_ happen. It's easy to forget that sometimes. 

Does this help? 

- Doctor Ian, The Math Forum
  http://mathforum.org/dr.math/   
    
Associated Topics:
High School Probability

Search the Dr. Math Library:


Find items containing (put spaces between keywords):
 
Click only once for faster results:

[ Choose "whole words" when searching for a word like age.]

all keywords, in any order at least one, that exact phrase
parts of words whole words

Submit your own question to Dr. Math

[Privacy Policy] [Terms of Use]

_____________________________________
Math Forum Home || Math Library || Quick Reference || Math Forum Search
_____________________________________

Ask Dr. MathTM
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/