The Vicar and the Curate (Ages of Three People)Date: 03/20/2002 at 23:20:40 From: Jason Mooney Subject: Crazy problem This is a problem that I just can't figure out. Please help. Note: Vicar and Curate are both terms for clergypersons (ministers, pastors, priests). These words are more commonly used in England than in the USA. Problem: THE VICAR AND THE CURATE A vicar and a curate, both with highly developed mathematical intelligence, were walking along a road, when they saw three people coming toward them. "Here is a little problem for you, curate," said the vicar. "The product of the ages of those three people is 2450 and the sum is twice your age. How old are those people?" The curate thought for a while and then said, "I cannot answer your question." The vicar, in turn, thought for a while and then said, "I see now. You are quite right, of course. Well, here is another piece of information, which will allow you to work the problem. I am older than any of those three people." HOW OLD IS THE VICAR? Date: 03/21/2002 at 01:33:47 From: Doctor Jeremiah Subject: Re: Crazy problem Hi Jason, The prime factorization of 2450 is: 2x5x5x7x7 That means the people could be only one of these sets of ages: 2, 5, 5x7x7 -> 2, 5, 245 -> sum = 252 2, 7, 5x5x7 -> 2, 7, 175 -> sum = 184 2, 5x5, 7x7 -> 2, 25, 49 -> sum = 76 2, 5x7, 5x7 -> 2, 35, 35 -> sum = 72 2x5, 5x7, 7 -> 10, 35, 7 -> sum = 52 2x5, 5, 7x7 -> 10, 5, 49 -> sum = 64 2x7, 5, 5x7 -> 14, 5, 35 -> sum = 54 2x7, 5x5, 7 -> 14, 25, 7 -> sum = 46 2x5x7, 5, 7 -> 70, 5, 7 -> sum = 82 2x7x7, 5, 5 -> 98, 5, 5 -> sum = 108 2x5x5, 7, 7 -> 50, 7, 7 -> sum = 64 Now the curate also knows that the sum is twice his age. He certainly knows his age and if one set of ages were uniquely twice his age he would have it figured out, so the only way he wouldn't have it figured out is if it were one of the two sets with the same age. 2x5, 5, 7x7 -> 10, 5, 49 -> sum = 64 2x5x5, 7, 7 -> 50, 7, 7 -> sum = 64 Both of these add to 64 so he can't know which of them is the right one (if it were any other it would be obvious that they were the only ones twice his age). Given the last clue, that the vicar is older than all three people, there are three possibilities for the vicar's age: 1. The vicar is younger than 50. 2. The vicar is 50. 3. The vicar is older than 50. In case 1, neither of the solutions would work. So the vicar can't be younger than 50. In case 3, his age doesn't resolve the ambiguity. So he can't be older than 50. That leaves case 2. The vicar must be 50. And if the vicar is 50, only one of the solutions will satisfy the constraint. 2x5, 5, 7x7 -> 10, 5, 49 -> sum = 64 Note that this ignores cases where one of the people is only a year old! But that doesn't really change the outcome of the problem, since they lead to unique sums. - Doctors Jeremiah and Ian, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994- The Math Forum at NCTM. All rights reserved.
http://mathforum.org/dr.math/