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Date: 03/25/2002 at 20:09:00
From: Arthur
Subject: Wierd math problem

If D=0 the point of this problem is to find out what all the letters
stand for knowing that d is equal to zero and the problem has to equal

Thanks,
Arthur R.
```

```Date: 03/26/2002 at 08:21:02
From: Doctor Ian
Subject: Re: Wierd math problem

Hi Arthur,

Here is the original problem:

ABCDC
- BEAAC
-------

We're told that D is zero - although that's not much of a hint. (Do
you see why it can't really be anything else?)  So we can substitute
that:

ABC0C
- BEAAC
-------
BA0A0

If we assume that each letter has to stand for a different digit, then
we can look at the tens place,

ABC0C
- BEAAC
-------
BA0A0
^
|

and see that we're going to have to carry a 1 from the hundreds place,
which means that 10-A = A.  The only digit that works for is 5, so we
can substitute that:

5BC0C
- BE55C
-------
B5050

Since we'd have to borrow from C, C must be 1 greater than 5, which means
it's 6.  So we can substitute that:

5B606
- BE556
-------
B5050

These steps illustrate the kind of thinking you have to do to solve this
kind of problem.

Can you take it from here?

- Doctor Ian, The Math Forum
http://mathforum.org/dr.math/
```
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