ABCDC - BEAAC = BADADDate: 03/25/2002 at 20:09:00 From: Arthur Subject: Wierd math problem ABCDC - BEAAC = BADAD If D=0 the point of this problem is to find out what all the letters stand for knowing that d is equal to zero and the problem has to equal BADAD. Thanks, Arthur R. Date: 03/26/2002 at 08:21:02 From: Doctor Ian Subject: Re: Wierd math problem Hi Arthur, Here is the original problem: ABCDC - BEAAC ------- BADAD We're told that D is zero - although that's not much of a hint. (Do you see why it can't really be anything else?) So we can substitute that: ABC0C - BEAAC ------- BA0A0 If we assume that each letter has to stand for a different digit, then we can look at the tens place, ABC0C - BEAAC ------- BA0A0 ^ | and see that we're going to have to carry a 1 from the hundreds place, which means that 10-A = A. The only digit that works for is 5, so we can substitute that: 5BC0C - BE55C ------- B5050 Since we'd have to borrow from C, C must be 1 greater than 5, which means it's 6. So we can substitute that: 5B606 - BE556 ------- B5050 These steps illustrate the kind of thinking you have to do to solve this kind of problem. Can you take it from here? - Doctor Ian, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994- The Math Forum at NCTM. All rights reserved.
http://mathforum.org/dr.math/