Summation Notation and Arithmetic SeriesDate: 07/27/2001 at 16:58:45 From: rachel Subject: Summation Notation and Arithmetic Series I have to use sigma notation with arithmetic series. I know how to use the equations for arithmetic series, but when I go to use sigma notation it seems as though a. I don't need these formulas, or b. I don't fully understand how to use k= and plug it in. Ex. 3+(4-1)3 3 = a 4 = n 3 = d What is k when I go to put it into sigma? Is it 3, or is it 1? 3 would mean it was f(k), and 1 would mean that I would need to multiply by d (3). Or do I not need to use the arithmetic series formulas when doing sigma notation, for I could just have sigma with k = 1, n = 4, followed by 3k. Thank you. Date: 07/27/2001 at 23:09:19 From: Doctor Peterson Subject: Re: Summation Notation and Arithmetic Series Hi, Rachel. The sigma notation really is just a different way to write the series itself, and has nothing to do with finding the sum. There, you still use the same formula when the time comes to find the sum. You haven't actually given me a series, and I'm not quite sure what it is that you did show. I suppose a is the first term, n is the number of terms, and d is the common difference, so your series is 3 + 6 + 9 + 12 with four terms, starting at 3 and increasing by 3 each time. Your 3+(4-1)3 must be the formula for the last term; the general kth term would be a_k = 3 + (k-1)*3 so that, for instance, when k = 1 it gives 3+(1-1)*3 = 3, and when k = 2 it gives 3+(2-1)*3 = 6. For each term in the series, k has a different value, 1, 2, 3, and 4. So k is not a specific number, but the index of any term. That is, it's a variable that changes from one term to another. The series, then, is the sum of these terms, with k taking values from 1 through 4. That's expressed in sigma notation this way: 4 +--- \ / 3 + (k-1)*3 +--- k=1 In this, I've said nothing I haven't said hefore: you can see the formula for the kth term, and the range of values taken by k, from 1 to 4. So this merely shows in an orderly way what the series is; it is just an alternative to writing out every term and saying 3 + 6 + 9 + 12 Now, if you are given the series in this form, and you want to find the sum, you have to do the same thing you'd do if you were given it in any other form: determine the values of a, d, and n (and the fact that it is, indeed, an arithmetic series), and plug them into the formula for the sum. Yor very last question suggests that you saw the right answer. As you pointed out, our formula for the kth term can be simplified, so that the series becomes 4 +--- \ / 3k +--- k=1 This makes it a little less obvious, perhaps, what the parameters of the series are. You can see from the fact that the kth term is linear that this is an arithmetic series, and by setting k = 1 can find the first term. If this doesn't fully answer your question, feel free to write back. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2015 The Math Forum
http://mathforum.org/dr.math/