How Did Eratosthenes Measure the Circumference of the Earth?Date: Wed, 26 Jun 1996 12:25:35 -0400 (EDT) From: Ed and Roxann Subject: Eratosthenes' method to find Earth's circumference How did Eratosthenes measure the circumference of the earth? As I understand the process, he measured the lengths of shadows of sticks at different locations on the same day and time of the year, so he had two right triangles, but they weren't similar. So what do I do? - Ed and Roxann Date: Wed, 26 Jun 1996 13:51:03 -0400 (EDT) From: Dr. Ethan Subject: Re: Eratosthenes' method to find Earth's circumference This will be a little hard to explain without a picture but I will do my best. Eratosthenes made a few assumptions. One was that the earth was a sphere and the other was that the sun's rays were parallel. Neither assumption is true, but both were close enough. We will make the same assumptions If the earth were flat and the sun's rays were parallel, if you put two sticks straight up a half mile away from each other then their shadow would make the same angle. But if the earth were curved, then the angle made by the shadows would be different. This difference can be used to figure out the circumference of the earth. Let's try an example. Let's say you are Eratosthenes in Athens and you have a stick sticking straight into the ground, and at high noon the sun is straight overhead so it leaves no shadow. But your friend is in Rome which is (I'm guessing) 400 miles away, and there at the same time the sun makes a shadow at a 30 degree angle. That means that in 400 miles what appears to be straight up and down is 30 degrees different from what it does in Athens. This means that you have moved 30 degrees around the Sphere (Earth) in those 400 miles. Well, since there are 360 degrees in a circle and 30/360 = 1/12, then 400 must be 1/12th of the total circumference of the Earth. So the circumference of the Earth is 12 * 400 or 4800 miles. Now take note: these numbers are made up and do not reflect Eratosthenes' calculations or the actual circumference of the Earth. Hope that helps. -Doctor Ethan, The Math Forum http://mathforum.org/dr.math/ Date: Wed, 26 Jun 1996 13:34:52 -0600 From: Ed and Roxann Subject: Re: Eratosthenes' method to find Earth's circumference Thanks, it's so easy now. I tend to get myopic when I start down the wrong path. Date: 06/15/2005 at 15:20:28 From: Greg Subject: Eratosthenes, circumference of earth and margin of error I have just read your version of the Eratosthenes story about finding the circumference of the earth and have seen it twice before. If I understand the story appropriately Eratosthenes was in Syene or Aswan and knew when the sun cast effectively no shadow, but how could he figure out the angle of the shadow at that same moment in Alexandria, 500 miles away? Also, the 500 miles is close to the correct distance but not as the crow flies, or not exactly as the arc of the earth. The timing, distance and rough measurements all seem to add up to an inaccurate but ingenious approach. Could you explain how he was so accurate given the margin of error of all the calculations? My thoughts are the timing of the shadow needs to be fairly accurate because the sun is in constant motion so the angle would be constantly changing. The ground and route taken from Syene to Alexandria is not exact either, what if the route was measured by circumventing natural obstacles or by measuring both up and down a hill? He was apparently within 4 percent, but that seems more luck than anything, even given Fermi's reasonableness estimations. Date: 06/15/2005 at 20:34:29 From: Doctor Rick Subject: Re: Eratosthenes, circumference of earth and margin of error Hi, Greg. Here is one site that explains the situation in some historical detail: Measuring the Solar System (Michael Fowler, UVa) http://galileoandeinstein.physics.virginia.edu/lectures/gkastr1.html I can't answer all your questions, but I can at least put one to rest. There is no significant issue with the timing of the sightings. If the sun is directly overhead, it must be noon (well, what navigators call "local apparent noon") when the sun is highest. The sun can't be any higher than straight overhead. It was known that on a certain day (the summer solstice) the sun passed directly overhead at Syene. All that was necessary in regard to timing was to measure the elevation of the sun at its highest point on that day. In celestial navigation, this is called a "noon sight" and is the easiest way to use a sextant to determine something about your position. Specifically, it tells you your latitude. All you need is a sextant and a table that gives the sun's elevation on each day of the year (or at closer intervals if you need more precision). You take a sight of the sun and continue adjusting the sextant until the sun starts going down. The highest value you found is the sun's elevation at local apparent noon. The important thing about a noon sight is that you don't need a precise timepiece to do it. For other sights you do need to know exactly when you took the sight, because the sun moves east to west a lot faster than it moves north and south, due to the earth's rotation. This is the reason that old maps have much more accuracy in their latitudes than in their longitudes: accurate chronometers had not been developed. Dava Sobel's book "Longitude" tells the fascinating story of how this situation was remedied at last. Back to Eratosthenes, a factor that you didn't mention is the accuracy of the observation that Syene is due south of Alexandria. That's a second-order error, though (the error in the result varies as the square of the error in east-west position); I agree that the error in measuring the distance if the roads weren't straight is probably the major source of error. But I don't know how great his errors were, or even whether we can know. The site I linked above says that the length of Eratosthenes' unit of distance, the stade, is not known for sure, so we can't be sure how accurate his result was. - Doctor Rick, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/