Geometric and Arithmetic MeansDate: 5/10/96 at 13:7:36 From: Sid Himes Subject: Geometric and Arithmetic Means Dear Dr. Math, My son is a junior at Harborcreek High School in Erie, PA. The following problem was part of a homework assignment (that has already been turned in). The textbook did not supply any solutions, at least none that I could find. Please give me an idea on how to tackle this problem: Find the values of two numbers whose sum is 20 and whose: a) geometric mean is 8 b) arithmetic mean is 8 Many thanks from a concerned father. Date: 11/14/96 at 21:52:00 From: Doctor Robert Subject: Re: Geometric and Arithmetic Means The geometric mean between two numbers x and y is sqrt(xy). So, if the two numbers must add to 20, let one of them be x. The other one must be 20-x. Now the geometric mean is sqrt(x(20-x)) = 8. Squaring both sides of this equation: x(20-x) = 64 -x^2 + 20x -64 = 0 Solving this for x you get x = 4, 16 The two numbers are 4 and 16 or, if you wish, 16 and 4. The arithmetic mean is nothing but the average. Again, the two numbers are x and 20-x and their average is 8: (x + 20-x)/2 = 8 20/2 = 8. This statement is never true. Therefore, there are no numbers which add to 20 and have an arithmetic mean of 8. If you think about it, any two numbers which add to 20 would have to have an arithmetic mean of 10. -Doctor Robert, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
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