Marble Collection Fraction ProblemDate: 9/9/96 at 21:30:53 From: Anonymous Subject: Tim and Danny's Marbles - Fraction Problem 3/4 of Tim's marble collection is the same size as 3/5 of Danny's collection. If they have 180 marbles altogether, how many marbles must Danny give to Tim so that they will have the same number of marbles? Thanks, Melissa Date: 9/11/96 at 12:15:6 From: Doctor Ana Subject: Re: Tim and Danny's Marbles - Fraction Problem This is definitely an algebra problem. I'm going to set it up and let you solve it. Feel free to write back if you need help doing the algebra. First of all, let's call the number of marbles that Tim has x. We could call Danny's marbles x if we wanted to, it doesn't matter, but I'm going to call Tim's marbles x. We know that there are 180 marbles between the two of them, so we know that Danny will have 180 - x marbles. Now we can set up the equation. 3/4 of Tim's marbles is the same as 3/4 * x, and 3/5 of Danny's marbles is the same as 3/5 * (180-x). So our equation is: 3/4 * x = 3/5 * (180 - x) To finish this problem, you can solve this equation for x, and that will tell you how many marbles Tim has. Then it will be easy to find out how many marbles Danny has, and from this you can figure out how many marbles Danny should give to Tim. -Doctor Ana, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994- The Math Forum at NCTM. All rights reserved.
http://mathforum.org/dr.math/