Associated Topics || Dr. Math Home || Search Dr. Math

### Solutions to Equations

```
Date: 01/16/97 at 19:38:59
From: Judy Holbrook
Subject: Pre-algebra

My problem is in pre-algebra. It is on equalities.  I can do most of
the ones that were assigned except for this one:

(3/4)y = -x

Here is one like it I have already done and know it is right:
3y = -7x.  You make a table similar to this showing the results:
x  y
0  0
7 -3
-7  3

Thanks!
```

```
Date: 01/20/97 at 04:05:02
From: Doctor Wallace
Subject: Re: Pre-algebra

Hi Judy!

You have been given an equation in two variables (x and y) and need
to come up with some solutions for x and y.  Since your example
problem has three listed solutions, I'm assuming you need only
three.  (Do you know how many total solutions there are to a problem
like this one?)

While we're on the subject of your sample problem, I think you got the
x and y values reversed.  You mean that for 3y = -7x the values should
be as follows:   x  y
0  0
-3  7
3 -7

Okay, now for (3/4)y = -x. This problem will be solved in exactly the
same way as you solved 3y = -7x. Choose any x value that you like.
Any one at all. Plug it into the equation where you see the x.
Then, solve for y.

For example, plug in 0. That's always pretty easy to work out. If we
plug 0 in for x, what do we get for y?

We would have (3/4)y = -0 which is (3/4)y = 0. This means that y
must also be 0, since 0 is the only number we could multiply (3/4) by
to get 0. So one solution is x=0, y=0.

Let's try another one. Choose a y value that you like. Any one at
all. Plug it into the equation where you see the y. Then, solve for x.
(This will also find a solution. You may choose a value for either
one, and then solve the equation to find the other.)

Let's choose 4 for y.  Plugging it in, we get:

(3/4) times 4 = -x, which gives 3 = -x

Now we multiply by -1, to get our answer:  -3 = x.

So our solution is x=-3, y=4.

Notice that choosing 4 for y made simplifying the left side of the
equation easier, since 4 is the denominator of 3/4. We could have
chosen any number for y, say 13, but then we'd have had 39/4 on that
side.  You can save yourself a lot of extra work by a wise choice of
x or y.

I hope this helps. Since you weren't specific on exactly where you
were having trouble solving this problem, I'm not sure I've answered
you very well. If not, write back!

-Doctor Wallace,  The Math Forum
Check out our web site!  http://mathforum.org/dr.math
```
Associated Topics:
Middle School Algebra
Middle School Equations

Search the Dr. Math Library:

 Find items containing (put spaces between keywords):   Click only once for faster results: [ Choose "whole words" when searching for a word like age.] all keywords, in any order at least one, that exact phrase parts of words whole words

Submit your own question to Dr. Math
Math Forum Home || Math Library || Quick Reference || Math Forum Search