Date: 04/16/97 at 14:24:23 From: JARED ROSS Subject: Algebra If two consecutive numbers are less than one hundred, what is the larger number?
Date: 06/25/97 at 17:10:03 From: Doctor Sydney Subject: Re: Algebra Dear Jared, Hello! Thanks for writing. In reading your question, we came up with a couple of different ways to interpret it, so we aren't quite sure what you mean. One way we might intepret the question is the following: 1. Suppose we have two consecutive numbers, each of which is less than 100. What is the larger number? Or, you might mean: 2. Suppose that we have two consecutive numbers such that their sum is less than 100. Then what is the larger number? This second question is more difficult than the first, so we'll assume that that is what you mean. However, if you were really asking the first question and still need help with it, write back, and we can help out. So, let's look at the second interpretation. Well, there are many pairs of numbers that when added up, equal less than 100. Think of it this way: If the two numbers must add up to be less than 100 (and we are only dealing with integers, which are numbers of the type ...,-3, -2, -1, 0, 1, 2, 3,...), then we can express what we want as: n + (n + 1) < 100 This says that n, plus the number that comes right after n, must be equal to a number less than 100. But we can make this even simpler! The equation can also be written as: 2n + 1 < 100 2n < 99 n < 49.5 So, for any pair of consecutive numbers (n, n+1) such that n < 49.5, the sum of the consecutive numbers is less than 100. For instance, the consecutive numbers (49,50) add up to less than 100. In fact 49 and 50 are the largest consecutive numbers that have this property. See if you can figure out why. Can you find other examples of consecutive numbers that work? I hope this helps you. Please write back if we answered the wrong question or if you need more help. -Doctors Matthew and Sydney, The Math Forum Check out our web site! http://mathforum.org/dr.math/
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