Two Step Equations
Date: 02/24/98 at 01:14:38 From: Tyler Raymond Subject: Two-step equations I do not understand how to figure out two-step equations. I think that I find a way and then find out that it does not apply to all cases. Here are examples of my problems to help you help me solve my problem. 7x - 2 = 12 8x + 3 = 19 Thanks for the help, Tyler Raymond
Date: 02/24/98 at 16:51:28 From: Doctor Rob Subject: Re: Two-step equations The aim is to isolate x on one side of the equation, so it looks like x = ... (or ... = x). Step 1: Identify the term not involving x on the same side of the equation as the x. It may be positive or negative. Step 2: Add its opposite (or negative) to both sides of the equation. (Alternately, subtract it from both sides of the equation.) Step 3: Simplify. (Notice that the "x" term is on one side of the equation, and a constant is on the other side.) Step 4: Identify the coefficient of x in the term involving x. It may be positive or negative. Step 5: Divide both sides of the equation by that coefficient. Step 6: Simplify. You're done! Your equation will now have the form "x = ...", which is what you were trying to get. Example: Solve 4*x + 7 = -13 for x. Step 1: That term is "+7". Step 2: Add -7 to both sides: 4*x + 7 - 7 = -13 - 7. Step 3: 4*x = -20. Step 4: That coefficient is 4. Step 5: 4*x/4 = -20/4. Step 6: x = -5. Now try your two problems. -Doctor Rob, The Math Forum http://mathforum.org/dr.math/
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