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Solving Systems of Equations Graphically and Algebraically
Date: 05/01/98 at 21:55:17
From: Audra Crystal Patterson
Subject: Algebra one(Graphing Systems of Equations)
I really do not understand how to work these problems:
y = -x
y = 2x
I have to graph each system of equations, then tell whether the system
has one solution, no solution, or infinitely many solutions. If the
system has one solution, name it. If you could please try and tell me
and give examples, maybe it would help me understand them better.
Thank you.
Audra Crystal Patterson
Date: 05/04/98 at 11:27:16
From: Doctor Loni
Subject: Re: Algebra one (Graphing Systems of Equations)
Let's see if I can help you at least a little bit. I will have to make
a few assumptions about what you have learned. (I will let you know
what I am assuming as we go along.) Each of the equations in your
example is a linear equation; in other words, the equation describes a
line. I am going to assume you know how to graph points and that you
know a little bit about lines.
If the two lines cross at one point, there is one solution to the
equations, and the solution is the x and y values of the point where
they cross (or intersect). If the two lines are parallel (the two
yellow lines down a highway are parallel lines -- they are always the
same distance apart), there is no solution, because they will never
cross. There are infinitely many solutions if the two equations define
the same line, which means they have every point in common.
Lines can be written in a form like this:
y = mx + b
where m and b are constants. m is the slope of the line, and b is the
point where the line crosses the y axis, also known as the y-
intercept. Just like the slope of a hill, the slope of a line is the
degree of slant. If two lines are parallel to each other, they will
have the same slope. So if you have two equations like this:
y = 2x + 6 and
y = 2x + 1
there will be no solution, because they have the same slope and will
never cross.
If two lines are not parallel, there are two ways to find the point at
which they intersect (which is the solution to the two equations):
1) You can do it graphically. If your equation is y = 3x, you could
put in values for x, solve for y, and then graph the points. For
instance, if x is 2, y would equal 6. You could graph that
point. Then pick at least one other value for x, find y, and
graph that point. Connect the dots, and you have a graph of your
line. Then you would graph the second equation in the same way,
and where they intersect would be the solution.
2) You can also find the point of intersection algebraically. For
example, say your two equations are:
y = 2x + 6 and
y = -4x
You can use the substitution method, where you solve one
equation for one variable, and plug in what you get into the
other equation. For instance, you already have:
y = -4x
You can put -4x in for y in the other equation:
y = 2x + 6
- 4x = 2x + 6
Solve for x:
x = -1
Now plug your value for x into one of the equations and solve
for y:
y = -4x
y = -4(-1) = 4
So the solution to the two equations is x = -1 and y = 4; or,
written as an ordered pair, (-1,4). That is the point where
those two lines would intersect.
Hope this is helpful. Let us know if you need more clarification.
-Doctor Loni, The Math Forum
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