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InequalitiesDate: 01/24/2001 at 22:08:56 From: Nick Kincannon Subject: Pre-Algebra How do you add, subtract, multiply, and divide inequalities?
Date: 01/26/2001 at 13:18:47
From: Doctor Alicia
Subject: Re: Pre-Algebra
Hi Nick,
When you add, subtract, multiply, and divide inequalities, you treat
the inequality as if it were an equation (=). You flip the inequality
if you divide or multiply by a negative number.
For example:
7 + 2x > 12
Subtract 7 from both sides:
7 - 7 + 2x > 12 - 7
2x > 5
Divide both sides by 2 but keep the inequality symbol as-is:
2x > 5
--- ---
2 2
x > 5
---
2
Therefore, x is greater than 5/2. To check our work, pick any x
greater than 5/2, such as 7/2.
7 + 2 * 7 > 12
---
2
The 2's cancel out:
7 + 7 > 12
14 > 12
So we see that our inequality holds true.
Now, let's try the a similar problem but one dealing with multiplying
or dividing negative numbers:
7 - 2x > 12
Subtract 7 from both sides:
7 - 7 - 2x > 12 - 7
- 2x > 5
Divide by *negative* 2 and flip the inequality:
- 2x < 5
--- ---
- 2 -2
The -2's cancel out:
x < -5
---
2
Therefore, x is less than -5/2. To check our work, pick a number less
than -5/2, such as -10.
7 - 2(-10) > 12
7 + 20 > 12
27 > 12
We see that the inequality holds true.
I hope this helps. Write back if you have any further questions.
- Doctor Alicia, The Math Forum
http://mathforum.org/dr.math/
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