Ship's BearingDate: 8/22/96 at 13:7:3 From: Anonymous Subject: Bearing of a Ship A ship travels 8km due east and then 8km due north. What is the bearing of the ship from its initial point? Date: 8/22/96 at 14:20:1 From: Doctor Paul Subject: Re: Bearing of a Ship the ship goes 8 km to the right and then 8 km up: /| / | / | / b | / | x / | / | / | / | 8 km / | / a c | ----------- -----> due east! 8 km You want to solve for the distance x. In this situation, we know that the two sides are the same length so we know that a and b are 45 degrees, while c is 90 degrees. In a 45,45,90 triangle, the length of the hypotenuse is the length of the side times the square root of two. So the distance x = 8*sqrt(2) = 11.314 and the bearing is 11.314 km at 45 degrees north of east. I hope this helps clear things up. -Doctor Paul, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
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