Scale Factor of Similar ShapesDate: 05/12/2000 at 12:00:32 From: Bobi Subject: Geometry Two regular octagons have sides of lengths 21 and 28, respectively. Find: A) the scale factor B) the ratio of the perimeters C) the ratio of the areas of the octagons I have no clue on how to do this at all. I haven't been able to figure out any of this. Thank you! Bobi Date: 05/12/2000 at 13:01:12 From: Doctor Peterson Subject: Re: Geometry Hi, Bobi. Do you know what a scale factor is? If you do, the first part is simple: it's just the ratio of the two numbers you were given. For the others, you can actually ignore what the shape is; you don't have to figure out the perimeter or area of the octagon. If two figures are similar (the same shape), as all regular octagons are, then the ratio of any length in the figure (such as a diameter, or the perimeter) will be the same as the scale factor, and the ratio of areas will be the SQUARE of the scale factor. You can see this more easily if you look at a square rather than an octagon. If the side of one square is S and the other is kS, the scale factor will be kS/S = k. The perimeters will be 4S and 4kS, and again the ratio is (4kS)/(4S) = k. The areas will be S^2 and (kS)^2 = k^2 S^2; the ratio of these is (k^2 S^2)/S^2) = k^2, the square of the scale factor. Do you see how the scale factor gets squared? When you find the area, you are multiplying two multiples of k together, so the scale factor appears twice in the answer. Perhaps you can guess that the ratio of volumes of similar solid figures is the cube of the scale factor. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/