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Factoring FractionsDate: 05/31/2001 at 17:44:48 From: Genise Gorman Subject: Adding fractions with unlike denominators I am having a major problem trying to figure out how to add fractions that have different denominators. I'm factoring, but once I factor I get completely lost. Can you help me, please, or at least give me a couple of ways of figuring this out? Thank you.
Date: 06/01/2001 at 12:34:23
From: Doctor Rick
Subject: Re: Adding fractions with unlike denominators
Hi, Genise.
You get lost while going through the Fraction Woods? Maybe a map will
help. There are landmarks along the way:
1. Find a common denominator, preferably the least common denominator.
2. Replace each fraction (if needed) by an equivalent fraction with
the common denominator.
3. Add the numerators of these equivalent fractions, and use the
common denominator when you write the sum.
4. Reduce the sum fraction to lowest terms ("cancel" any common
factors in the numerator and denominator).
It sounds like you're getting lost on your way to the first landmark.
For the time being, you can make this step easier by NOT trying to
find the LEAST common denominator. The product of the two denominators
is a perfectly acceptable denominator. You'll have to go farther in
the last leg of the trip - the numbers will be bigger, and you're more
likely to find common factors. But you'll be close to the edge of the
woods by then, so you may be less likely to get lost.
Here's an example, using the least common denominator first, then just
using the product of the denominators.
7 5
--- + --- = ?
20 36
Step 1: Find the least common denominator of 20 and 36. Their prime
factorizations are
20 = 2*2 *5
36 = 2*2*3*3
-----------
LCD = 2*2*3*3*5 = 180
Where the two factorizations have a factor in common, I wrote one
below the other. The numbers in a column are always the same. Then to
find the LCD, I took one number from each column, and multiplied them
together.
Step 2: Find equivalent fractions with denominators of 180.
To convert 7/20 to a fraction with a denominator of 180, we have to
multiply the denominator (20) by 9. To keep the fraction equivalent,
we have to multiply the numerator by the same number (9).
7 7*9 63
--- = ---- = ---
20 20*9 180
To convert 5/36 to 180ths, we have to multiply the numerator and
denominator by 5:
5 5*5 25
--- = ---- = ---
36 36*5 180
Step 3: Add the numerators and use the common denominator.
63 25 88
--- + --- = ---
180 180 180
Step 4: Reduce to lowest terms. To do this, we factor the numbers:
88 = 2*2*2 *11
180 = 2*2 *3*3*5
The common factor is 2*2 = 4. Divide each number by 4 (or keep the
factors in each number that aren't in the other number) to get
88/4 22
----- = --
180/4 45
Now I'll do the same problem with the simpler first step.
Step 1: Find a common denominator by multiplying the two denominators.
20 * 36 = 720. (That's bigger than the first way, but it's okay.)
Step 2: Find equivalent fractions with this common denominator. To
convert 7/20 to 720ths, we need to multiply the numerator and
denominator by 36.
7 7*36 252
--- = ----- = ---
20 20*36 720
To convert 5/36 to 720ths, we have to multiply the numerator and
denominator by 20.
5 5*20 100
--- = ----- = ---
36 36*20 720
Step 3: Add the numerators and use the common denominator.
252 100 352
--- + --- = ---
720 720 720
Step 4: Reduce to lowest terms. To do this, factor each number:
352 = 2*2*2*2*2 *11
720 = 2*2*2*2 *3*3*5
The common factor is 16. Divide 352 by 16 (or keep the factors that
aren't in the factorization of 720) to get 22. Divide 720 by 16 (or
keep the factors that aren't in the factorization of 352) to get 45.
The answer is 22/45, the same answer I got the first time.
Perhaps my example of how to find the LCD will help keep you from
getting lost. If so, do it the first way. If you still tend to get
lost, try the second way.
If you need more ideas, our Dr. Math Archives contain lots of answers
to questions about adding fractions. Just go to our Search Dr. Math
page:
http://mathforum.org/mathgrepform.html
type in the words:
adding fractions
select "that exact phrase," and click the Search button. Maybe one of
these answers will help you.
- Doctor Rick, The Math Forum
http://mathforum.org/dr.math/
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