Please graph and send the solution for:
Date: 23 May 1995 16:43:06 -0400 From: J. Poholsky's grade6A Charles River Subject: math problem Please graph and send the solution for: x^2/2 + y^2/2 = 0 from Katie Allen and Kim Wilson problem from Mr. Rob Hunt 6th grade teacher at Charles River School in Dover Ma.
Date: 24 May 1995 00:37:13 -0400 From: Dr. Sydney Subject: Re: math problem Dear Katie and Kim, Hello! This problem is a bit tricky, but once you find the answer it seems to be not so bad! Let's first play around with the equation you gave us. Let's multiply by 2 to get: x^2 + y^2 = 0 Now, we know that when we square any real number, we get a number greater than or equal to 0, right? If the real number is not zero, its square is greater than 0; if the real number is 0, its square is 0. So, why don't you consider 4 cases: Case 1: x and y are both nonzero Case 2: x is nonzero but y is zero Case 3: x is zero and y is nonzero Case 4: x and y are both zero This will cover all possible cases, right? For each case, determine whether or not there are any x's and y's that will work in your equation. For example, in Case 1, since x and y are both nonzero, x^2 will be greater than 0 and y^2 will be greater than 0. That means x^2 + y^2 will be greater than 0. Thus, there are no x's and y's that are both nonzero such that your equation holds. Test the other 3 cases, and you will come up with an answer! If any of this is confusing, or if you want to check your answer, feel free to write back! --Sydney, "Dr. Math"
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