|


FactorizationDate: 03/17/99 at 22:34:02 From: karen Subject: Factorisation Can you help me simplify 9b^2 - 24bc + 16c^2?
Date: 03/18/99 at 10:33:19
From: Doctor Rick
Subject: Re: Factorisation
Let us look at your goal. You want to get it in this form:
2 2
9b - 24bc + 16c = (Mb + Nc)(Pb + Qc)
You need to replace the 4 letters M, N, P, and Q with numbers so you
will get the right coefficients.
The product MP must be 9, so M and P could be 1 and 9 or 3 and 3.
(Order does not matter, since it is just a matter of which set of
parentheses comes first.)
The product NQ must be 16, so N and Q could be 1 and 16, 2 and 8, or
4 and 4. If M and P are 1 and 9 then order matters, so you would need
to try 16 and 1, as well as 8 and 2.
The sum of the inside and outside products (MQ + NP) will be -24
(remember the sign). Since it is negative, we must have at least one
negative number, N or Q. But since NQ is positive, BOTH N and Q must
be negative.
There are quite a few possibilities to try. But since both 9 and 16
are perfect squares, my instinct says to try the squares first:
M = 3
P = 3
N = 4
Q = 4
Now make that N = -4, Q = -4 since they must be negative.
Try this out:
(3b - 4c)(3b - 4c) = 9b^2 - 12bc ... 3b(3b-4c)
- 12bc + 16c^2 ... -4c(2b-4c)
-------------------
9b^2 - 24bc + 16c^2
Sure enough, it works! Just for practice, let us see what would have
happened if we tried something else first. What if M = 1, P = 9, and
N = -8, Q = -2?
MQ + NP = (1)(-2) + (-8)(9)
= -2 - 72
= -74
That is not close to -24, so we would have to try another combination.
As you do enough of these, you will develop a feel for what might work
and what will not. For instance, you will get a smaller (absolute
value) bc term if you put the bigger numbers either both first or both
last, so they do not get multiplied together in the cross term (bc).
With M = 1, P = 9, and N = -2, Q = -8:
MQ + NP = (1)(-8) + (-2)(9)
= -8 - 18
= -26
That is a lot closer to what we wanted (-24). My reasoning turned out
to be correct. Of course, we already have the answer, and it is not
very close to what I just tried. There is a lot of trial and error in
factoring, but as I said, you can develop a feel for it.
- Doctor Rick, The Math Forum
http://mathforum.org/dr.math/
|
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]


Ask Dr. MathTM
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/