Distance, Rate, and Time Problems
Date: Wed, 22 Mar 1995 14:17:25 AST From: Richard Seguin Subject: Rate, Distance, Time... I have a question like this: 1) Liza and Tamar leave the same camp and run in opposite directions. Liza runs 2m/s and Tamar runs 3m/s. How far apart are they after 1 hour? What I did was: Liza ---- Have to convert from Sec to hours. 3600 = sec in hours (2m/s)(3600)=7200 M/H Now I converted it to KM: 7200M = 7.2KM So she would be 7.2KM Tamar: ------ (3M/S)(3600)=10800M/H Converted to KM 10800 = 10.8 KM They all together would be 18KM apart. Right?
Date: 10 Apr 1995 15:09:40 -0400 From: Dr. Ethan Subject: Re: Rate, Distance, Time... You got it. Good work, Richard. If you have any more questions or need any help please write back. Ethan Doctor On call
Date: 10 Apr 1995 17:31:33 -0400 From: Richard Seguin Subject: distance,time,and rates What about this: 4) Jon and Jennifer start at the same point and ride their bicycles in the same direction. Jon travels at 12km/h, while Jennifer travels at 16km/h. After 6h, how far apart are they? What I did was: Jon --- D=Vt D=(12)(6) D=72KM Jennifer -------- D=VT D=(16)(6) D= 96KM 96-72 = 24 Km apart Is this right? I think I am getting the hang of this.
Date: 10 Apr 1995 17:31:33 -0400 From: Dr. Ethan Subject: Re: distance,time,and rates Yep, that one is right too. Ethan Doctor ON Call
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