Tea Blend: Price of Inferior TeaDate: 6/24/96 at 7:20:39 From: Anonymous Subject: Tea Blend: Price of Inferior Tea 6kg of inferior quality tea are mixed with 3kg of high quality tea which costs $2.00 per kilogram more than the inferior tea. The total price of the mixture is $24.00. What is the price of the inferior tea? I started with the formula : x + x+2 = 24 but could not go further. - --- 6 3 Can you let me know how to determine the correct formulae to use? I don't have a problem with using algebra; the difficulty I am experiencing is how to work out the formula required to solve the problem. Help! Date: 6/24/96 at 8:17:40 From: Doctor Anthony Subject: Re: Tea Blend: Price of Inferior Tea Remember to define terms before you write down the equations. I will let x = price per kg of the cheap tea x+2 = price per kg of expensive tea Total cost will be 6x + 3(x+2) = 24 6x + 3x + 6 = 24 9x = 18 x = 2 So cheap tea is $2 per kg. -Doctor Anthony, The Math Forum Check out our web site! http://mathforum.org/dr.math/ Date: 6/26/96 at 10:38:8 From: Doctor Jerry Subject: Re: Tea Blend: Price of Inferior Tea If the total cost of the inferior tea is x dollars per kg, then the total cost of the quality tea is (x+2) dollars. Then, 6 kg of the inferior tea will have value 6x dollars (this is kg times dollars per kg) and the 3 kg of quality tea has value 3(x+2) dollars. Total value if 24 dollars. So 6x+3(x+2)=24. Solution is x=2 dollars. In your equation, the units don't balance. On the left, you have kg divided by kg. On the right, just dollars. -Doctor Jerry, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
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