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Garden AreasDate: 8/14/96 at 13:51:21 From: Anonymous Subject: Algebra Word Problems Dear Dr. Math, I am an English teacher you have helped before. I hope you can help me again. I am on the chapter involving factoring and the zero product property. Here is a word problem with which I am having a difficult time: One year, Josef put in a rectangular garden, with its length 5 feet more than its width. The next year, he increased the length by 3 feet and decreased the width by 2 feet. If the area of the second garden was 119 sq. feet, was the second garden larger or smaller?
Date: 8/14/96 at 22:57:59
From: Doctor Robert
Subject: Algebra Word Problems
Label the dimensions of the FIRST garden, x and x+5, where x is the
width and x+5 is the length.
Now, according to the problem, the SECOND garden must have a length of
x+8 and a width of x-2. So we have the following equation:
(x+8)(x-2) = 119
--> x^2 + 6x -16 = 119
--> x^2 + 6x - 135 = 0
--> (x+15)(x-9) = 0
Therefore, x = -15 or x = 9. We reject the negative value because
though it satisfies the equation, it does not apply to our problem.
The answer is x = 9. So the FIRST garden must have measured 14 by 9
and the SECOND garden 7 by 17. The first garden is bigger.
Cheers.
-Doctor Robert, The Math Forum
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