Associated Topics || Dr. Math Home || Search Dr. Math

Leaky Ship

```
Date: 08/30/97 at 00:50:08
From: windows
Subject: Leaky Ship

A ship has sprung a leak. Water is coming in at a uniform rate and
some has already accumulated when the leak is detected. At this point
12 men of equal skill can pump the ship dry in 3 hours, while 5 men
require 10 hours. How many men are needed to pump it dry in 2 hours?
```

```
Date: 09/03/97 at 10:47:03
From: Doctor Rob
Subject: Re: Leaky Ship

Let the amount of water in the ship be W. Let the rate of leakage be
R gallons per hour. Then the amount of water which has to be pumped
out after H hours is W + R*H. Let the amount of water one man can pump
in 1 hour be M. Then 3*12*M = W + 3*R, and 5*10*M = W + 10*R.
Eliminating W, we find that R = 2*M. Substituting, we find W = 30*M.

Let x be the number of men required. Then x*2*M = W + 2*R, which you
can solve for x.

-Doctor Rob,  The Math Forum
Check out our web site!  http://mathforum.org/dr.math/
```
Associated Topics:
Middle School Word Problems

Search the Dr. Math Library:

 Find items containing (put spaces between keywords):   Click only once for faster results: [ Choose "whole words" when searching for a word like age.] all keywords, in any order at least one, that exact phrase parts of words whole words

Submit your own question to Dr. Math
Math Forum Home || Math Library || Quick Reference || Math Forum Search