DenominatorsDate: 12/31/97 at 17:14:50 From: Mike Newman Subject: Denominators I have a problem with different denominators... 4/5+5/6+7/16 = ? What is the best and fastest way to find the LCD? Thanks, Mike Newman Date: 01/01/98 at 14:52:20 From: Doctor Mike Subject: Re: Denominators Hi, It's always nice to hear from another Mike - and there are a lot of us out there. The short answer to your question is "Prime Factorization," but let me explain that. Prime numbers are those whole numbers greater than 1 which are divisible only by themselves and one. Your first denominator 5 is a prime number, but the second is not because 6 = 2*3. Also, the third denominator is not because 16 = 2*2*2*2. These primes you multiply together to get the number are called the prime factors. Notice that some of the factors get repeated. IF you do not have to find the *least* common denominator, but just any old common denominator, then you multiply the three together, i.e., 5*6*16 = 480. This is the easiest common denominator to find, but usually not the easiest one to work with. The *least* common denominator has to have all the factors for all the denominators. In this case it is 2*2*2*2*3*5 = 240 It has the four 2's for 16. It has the 2 and 3 for 6. It has the 5 for 5. But notice that one of the 2's for 16 also serves as the 2 for 6. This is somewhat of an improvement over 480. Sometimes the improvement is much better. For instance, if the denominators are 60 and 10 and 15 and 3, the product of all 4 denominators is 27000, but the least common denominator is 2*2*3*5 = 60 .... quite a bit simpler! So, the best and fastest way to find the least (smallest) denominator that works is to factor all the denominators until you cannot factor them any more, and then construct the new denominator to have *just enough* of all the prime factors involved. I hope this helps. Since you asked about finding the LCD I assume that you can take it from there to convert the 3 fractions to equivalent fractions with 240 as the denominator, and then add. -Doctor Mike, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994- The Math Forum at NCTM. All rights reserved.
http://mathforum.org/dr.math/