Zero Point of Thermometer
Date: 04/06/2002 at 08:09:59 From: Mark Subject: Zero point of thermometer What is the zero point of a thermometer? Is it 0 degrees of any temperature scale, or 0 Kelvin, or -273.15 Kelvin? I know how to convert the scales to the other scales. Just what is the zero point? How would you find the zero point on a thermometer?
Date: 04/06/2002 at 09:27:34 From: Doctor Tom Subject: Re: Zero point of thermometer Hi Mark, That's a good question. In every temperature scale, the temperature of a substance rises by one degree when a specific amount of thermal energy is added to the substance. This "specific amount" differs, of course, with different scales. Since the Centigrade steps are bigger than the Fahrenheit steps, the amount of energy you need to add to go up one degree Centigrade is more than the amount needed to go up one degree Fahrenheit. But the idea is this: if you start at any temperature and add that amount of energy, the temperature goes up one degree. If you add that amount again, the temperature goes up another degree, etc. Remember that it's thermal energy only that counts. If you're melting ice, for example, you add a lot of energy, but the temperature doesn't rise, since the energy you're adding is to overcome the heat of fusion of ice - the energy required to convert ice at freezing to water at freezing. So temperature goes up linearly with added thermal energy, but where is the zero point? The first reasonable system was the Fahrenheit system. Since the inventor of the system had no idea of absolute zero, he just chose for his zero the coldest temperature that was, at the time, available in a laboratory (the temperature of ammonium chloride in ice water). Then he needed to pick another point and assign it a number, and everything else would be fixed. He chose human body temperature as 100 degrees (obviously he had a very slight fever when he measured this, since normal body temperature is around 98.6 degrees Fahrenheit.) Of course this was long ago, and soon colder things were found, so negative temperatures were required. Centigrade was more scientific, in a sense, since its endpoints were chosen in a purely physical way: 0 degrees for freezing pure water and 100 degrees for boiling pure water (at standard pressure - sea level, or 760mm Hg). Of course Centigrade also needed negative temperatures. Later, the study of thermodynamics showed that there is an absolute zero. In other words, you can't just keep removing thermal energy forever, and once it's all gone, the temperature can't go lower. This is VERY cold: -273.15 degrees Centigrade. A more reasonable temperature in some sense, is the Kelvin scale, where absolute zero is chosen to be zero. But since all the scientific data were/are in terms of one-degree steps in the Centigrade scale, 0 degrees Kelvin is chosen to be -273.15 degrees Centigrade, and the freezing point of water is chosen to be 273.15 degrees Kelvin. (Actually, I think Kelvin is technically defined with the triple point of water which is .01 degree different from the freezing point at standard pressure. The triple point is where solid, liquid, and gaseous water all exist at equilibrium, and this determines not only a temperature and a pressure, but is very easy to duplicate and does not require a pressure measurement.) There's also something called the Rankind scale that's like the Kelvin scale but uses steps of the Fahrenheit size. It's hardly ever used. To convert from Centigrade to Kelvin, add 273.15 degrees. To convert from Centigrade to Fahrenheit, use this formula: C = (5/9)(F-32) So the situation is a little strange, but we're stuck with it for historical reasons. Perhaps an even better way to do it would be to define 0 degrees as absolute zero and 100 degrees as the triple point of water. But then the size of a degree would change, and all scientific publications that have ever been written that mention a temperature would be out of date, and that would certainly not be worth the trouble. - Doctor Tom, The Math Forum http://mathforum.org/dr.math/
Search the Dr. Math Library:
Ask Dr. MathTM
© 1994-2013 The Math Forum