Solving for One Variable of ManyDate: 05/30/2002 at 20:31:37 From: Makeia Gay Subject: I need help I don't understand how to solve formulas for specific variables. For example, solving Ax + C = D for x. Date: 05/31/2002 at 14:25:22 From: Doctor Ian Subject: Re: I need help Hi Makeia, Solving for one equation is a little like untying a knot. You have an x in the middle of all this stuff, and you have to get it out. The basic rules are: 1. You can add anything to both sides of an equation. 2. You can multiply both sides of an equation by anything. 3. You can't divide by zero! Note that sometimes 'add' means 'add a negative number' (which is like subtracting), and 'multiply' means 'multiply by a fraction' (which is like dividing). You do additions and multiplications in order to move things from one side of the equation (where you don't want them) to the other. So let's look at ax + c = d We don't want the x on the same side as the x, so we can add -c to both sides of the equation. ax + c + -c = d + -c On the left side, the c and -c cancel each other out, so we get ax = d - c Now we'd like to get rid of the a. We can do that by multiplying by (1/a): (1/a) * ax = (1/a)(d - c) x = (d - c)/a And now we have x by itself on one side, which is what we wanted. Note that the order of the operations is important! We had to add -c, and then multiply by (1/a). If we had done those things in the opposite order, we'd have ended up with a mess. Note also that when you multiply one side of an equation by something, you multiply _everything_ on that side. Usually you do this by putting parentheses around it, to remind yourself. If we'd done something like (1/a)*x = (1/a)d - c we'd have ended up with the wrong answer. But this is a common error, and you have to watch out for it. I hope this helps. - Doctor Ian, The Math Forum http://mathforum.org/dr.math/ |
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