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Height of IntersectionDate: 01/16/2003 at 21:24:11 From: Rick Subject: Advanced geometry There are two flagpoles with heights of 10 feet and 70 feet respectively that are 100 feet apart on a level surface. If a line ran from the top of each pole to the bottom of the other, what would be the height of intersection? Create a formula using one variable I've concluded through diagrams that the distance apart has nothing to do with the location of the intersection because both the lines are moving proportionately, so the variable must be height.
Date: 01/16/2003 at 23:31:59
From: Doctor Peterson
Subject: Re: Advanced geometry
Hi, Rick.
You're right that everything depends not on the actual distance, but
simply on proportions. What if we ignore the 100 in the problem, and
just use variables for the two horizontal distances and the height of
the intersection? (I don't see what the "formula using one variable"
might be; but perhaps if we start with three variables, we'll see
things simplify.)
Here's the setup:
+
| \
a| \ +
| X |b
| / h| \ |
+-----+---+
x y
Here a and b are the two heights, 70 and 10 in the original problem;
I like to use variables (in this case, named constants) rather than
numbers in problems like this where the specific numbers could easily
be replaced with others, because that can give me more insight into
the nature of the problem. The height we are looking for is h, and x
and y are the horizontal distances.
Now I see two pairs of similar triangles. I'll set up two proportions,
one relating a to h, and the other relating b to h. That gives two
equations, which can then be solved to eliminate x or y. It turns out
that both x and y can disappear; if you don't find that happening
naturally as you solve the equations, try using each equation
separately to get an expression for x/y in terms of a, b, and h, then
set those equal. This will give you an equation you can solve for h;
in fact, that might be the "formula" you are supposed to find. And
it's the fact that only the ratio x/y matters, not the sum x+y, that
your insight revealed.
If you have any further questions, feel free to write back.
- Doctor Peterson, The Math Forum
http://mathforum.org/dr.math/
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