Find the BearingDate: 01/17/2003 at 19:47:43 From: Richard Subject: A formula to find the bearing of one point from another. Is there a formula to find the bearing of one point from another on a 2D map (or graph) just using normal co-ordinate systems? (I want to avoid talking about the great circle (it's 2D) and longitude and latitude.) Thanks for your help. Date: 01/17/2003 at 20:32:42 From: Doctor Rick Subject: Re: A formula to find the bearing of one point from another. Hi, Richard. Do you mean a Cartesian x-y coordinate system, calibrated the same in x and y directions (unlike latitude-longitude, in which a minute of longitude is a different distance from a minute of latitude)? If so, then the basic formula is pretty easy. The bearing from point (x1,y1) to point (x2,y2), in degrees east of north, is bearing = 90 - arctan((y2-y1)/(x2-x1)) This will always give an angle between 0 and 180 degrees (assuming your arctan function returns degrees). You need to adjust it to take account of the orientation of the line. I think this will do the job: dx = x2-x1 dy = y2-y1 if dx > 0 then bearing = 90 - arctan(dy/dx) if dx < 0 then bearing = 270 - arctan(dy/dx) if dx = 0 then if dy > 0 then bearing = 0 if dy < 0 then bearing = 180 if dy = 0 then point 1 = point 2 and there is no bearing If you are programming and you have a function atan2(y,x), all this is handled for you. Most likely atan2 returns an angle in radians, so I'll put in the conversion to degrees: bearing = 90 - (180/pi)*atan2(y2-y1, x2-x1) Note: Sometimes (as in Excel) atan2 takes switched arguments: atan2(x,y). - Doctor Rick, The Math Forum http://mathforum.org/dr.math/ Date: 01/18/2003 at 07:39:21 From: Richard Subject: Thank you (A formula to find the bearing of one point from another.) Thanks very much for that! |
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