Eisenstein's Irreducibility CriterionDate: 02/26/2003 at 06:35:17 From: Ken Lai Subject: Eisenstein's Irreducibility Criterion Is the criterion only a sufficient condition for a polynomial to be irreducible, since I find that there are many irreducible polynomials that do not meet the criterion. Examples are: a) x^2 + 3x + 4 Here no common prime number exists that divide coefficients 3 and 4 b) x^2 + 4x + 8 Here p=2 but p^2 divides 8, which violates the 3rd axiom of the criterion. So it appears to me that that being a sufficient condition, such sets of irreducible polynomials that meet the E. Criterion are subsets of a bigger set of irreducible polynomials. Is my perception correct ? Thanks and regards, Ken Lai Date: 02/26/2003 at 07:01:27 From: Doctor Jacques Subject: Re: Eisenstein's Irreducibility Criterion Hi Ken Lai, You are correct, the criterion is merely sufficient, not necessary. Note that, in some cases, you may have an irreducible polynomial that does not satisfy the criterion, but you can transform it in such a way that the new polynomial does satisify it. For example, consider your first example: x^2 + 3x + 4 If you make the substitution x = y + 1 you get y^2 + 5x + 5 which does satisfy Eisenstein's criterion. As both polynomials would be simultaneously reducible or not (you can also do the substitution after factoring), this proves that the initial polynomial is irreducible over the rationals. Of course, you need some luck to use this trick. Please feel free to write back if you want to discuss this further. - Doctor Jacques, The Math Forum http://mathforum.org/dr.math/ |
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