Length of Coiled BeltDate: 04/11/2003 at 23:36:31 From: Manny Rivas Subject: Length of coiled belt Working with conveyor belts we use a formula that gives a very close approximation of the length of a coil of belt, but I would like to know the reasoning of it. The outside and inside diameters of the coil (in inches) are added and then multiplied by the number of wraps, this is then multiplied by a constant (.1309), and the result is to be read in feet. It works, but I would like to know why. I tried to reason it out but I am stumped. Date: 04/12/2003 at 23:38:30 From: Doctor Peterson Subject: Re: Length of coiled belt Hi, Manny. We have a number of answers to questions about the length on a roll of some material; one of them may give a formula like this based on the number of turns. The cross sectional area of the coil is the difference between the circle formed by the outer diameter, D, and that formed by the inner diameter, d: A = pi (D/2)^2 - pi (d/2)^2 = pi/4 (D^2 - d^2) The cross-sectional area of the belt straightened out is A = TL where T is the thickness and L is the length. Setting these equal, TL = pi/4 (D^2 - d^2) But T can be found by dividing (D-d)/2 by the number of turns N: (D-d)/(2N) L = pi/4 (D^2 - d^2) Solving for L, L = pi/4 2N (D^2-d^2)/(D-d) Since D^2 - d^2 = (D-d)(D+d), this is L = pi/2 N (D+d) That is your formula; to convert inches to feet we have to divide by 12, and (pi/2)/12 = 0.1309. If you have any further questions, feel free to write back. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/ |
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