Date: 04/28/2003 at 08:13:37 From: Rami Subject: Maths A Web page of 10 megabytes is being retrieved from a Web server. What is the time to transfer the page over a modem operating at 28.8kbps? According to my professor we have to divide something by 8.
Date: 04/28/2003 at 09:23:28 From: Doctor Edwin Subject: Re: Maths Hi, Rami. This is not really a mathematics question; it's really about the units used to measure size and capacity in computer equipment. The basic unit of data in computing is one bit - a one or a zero. Bits are almost always used in chunks, and the smallest chunk is usually a byte, or 8 bits. Bit is abbreviated with a lower-case b, and byte is abbreviated with an upper-case B. When we measure the size of a file, we typically do so in bytes (or megabytes). Network and dialup connection speeds are generally measured in bits per second, abbreviated with a lower-case b. So your file is 10MB (Megabytes) or 80 Mb (megabits), while your connection speed is 28.8 kbps (kilobits per second). One other thing: In computing, kilo and mega don't exactly mean 1,000 and 1,000,000. Almost always, kilo means a "binary thousand" or 1024 (2^10). So a megabyte is 2^20, or 1024^2. So your file is actually 10 * 1024 * 1024 * 8 bits. Hope this helps. Write back if you have any more questions. - Doctor Edwin, The Math Forum http://mathforum.org/dr.math/
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