|


BijectionsDate: 04/28/2003 at 13:08:03 From: Mandy Subject: Bijections Find a bijection from (0, 1) to (0, 1]. (Be sure to prove that your function has the proper properties.)
Date: 04/28/2003 at 16:52:15
From: Doctor Rob
Subject: Re: Bijections
Thanks for writing to Ask Dr. Math, Mandy.
The trick here is to pick a countably infinite subset S of (0,1).
Let S = {x[1],x[2],x[3],...}. Then define your function
f:(0,1)->(0,1] by
f(x[1]) = 1,
f(x[n+1]) = x[n] for all n >= 1,
f(x) = x for all x in (0,1) but not in S.
Then prove that f is one-to-one and onto (that is, a bijection).
Feel free to write again if I can help further.
- Doctor Rob, The Math Forum
http://mathforum.org/dr.math/
|
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]


Ask Dr. MathTM
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/