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Find the Area of the QuadrilateralDate: 05/20/2003 at 00:18:57 From: N. Arun Subject: Geometry Vertex Q of square QRST is at the center of square MNOP. The length of a side of MNOP is 1 and the length of a side of QRST is 2. Side QR intersects OP at X and QT intersects MP at Y. If angle QXP is 60, the area of quadrilateral QXPY is [1] ((3^0.5)/6) [2] 1/3 [3] 1/4 [4] ((2^0.5)/4) I don't know how to calculate the area of a quadrilateral using only the vertex angles.
Date: 05/21/2003 at 12:28:09
From: Doctor Peterson
Subject: Re: Geometry
Thanks for writing to Dr. Math.
Here is my version of the figure; since the size of QRST doesn't
matter, I only show Q and the edges connected to it:
N-------------------------------------------O
| |
| |
| | ----
| | ----
| -X-
| ----.|
| ----.....|
| ---.........|
| ----............|
| ----................|
| Q---------------------A
| |\....................|
| | \...................|
| | \..................|
| | \.................|
| | \................|
| | \...............|
| | \..............|
| | \.............|
| | \............|
| | \...........|
M---------------------B----------Y----------P
\
\
Think about how you can find the areas of triangles QAX and QBY;
don't actually calculate them just yet. How would you use those areas
to find the area of QXPY? One approach is to compare it with square
QAPB.
Do you see a very easy way to find the area?
- Doctor Peterson, The Math Forum
http://mathforum.org/dr.math/
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