Anaesthetic ConcentrationDate: 07/21/2003 at 17:02:43 From: Joanne Subject: Concentration of drugs for anaesthetics What is the % concentration when you constitute 100ml water with 2.5g of thiopentone? I'm not sure that it is as simple as 2.5% Date: 07/22/2003 at 05:56:57 From: Doctor Achilles Subject: Re: Concentration of drugs for anaesthetics Hi Joanne, Thanks for writing to Dr. Math. First of all, I should note that mixing anaesthetics is an extremely sensitive thing and it should only be done by a certified professional. Having said that, you are correct, the answer is 2.5%. Because 1ml of water has a mass of 1g, 100ml will weigh 100g. 2.5g of solute in 100ml total will be approximately 2.5g of solute in 100g total. 2.5/100 equals 0.025 or 2.5%. Actually, to be more precise, the answer is: 2.5% (w/v) The "(w/v)" is short for "weight per volume." The reason is that the solute (anaesthetic) is measured by weight (or mass), and the solvent (water) is measured by volume. So the numerator of your fraction is weight and the denominator is volume. I hope this helps. If you have other questions or you'd like to talk about this some more, please write back. - Doctor Achilles, The Math Forum http://mathforum.org/dr.math/ Date: 07/23/2003 at 14:21:32 From: Joanne Subject: Re: Concentration of drugs for anaesthetics But when you add 2.5g to 100g of water, don't you end up with 102.5g of solution? So shouldn't it be 2.5g divided by 102.5g? Date: 07/23/2003 at 15:42:26 From: Doctor Achilles Subject: Re: Concentration of drugs for anaesthetics Hi Joanne, Notice how I said "2.5g of solute in 100ml *total*", rather than "2.5g of solute in 100ml *of water*". The appropriate way to mix a solution of a given weight/volume is to first make a more concentrated solution. In the case of making 100ml at 2.5% (w/v), what I would do is get about 70ml of water and disolve 2.5g of solute. I would then adjust the volume with additional water until a final volume of 100ml is reached. If we assume that the final density is 1g/ml, then we will have created a 2.5% solution (by weight). However, because our solution is (by definition) not 100% pure water what we have instead is 2.5g in 100ml. The notation "2.5% (w/v)" is identical to saying "2.5g in 100ml of aqueous (i.e. mostly water) solution". We could make a solution of precisely 2.5g (by weight) if we modified the protocol slightly: Again, we could start with 70ml of water, add 2.5g of solute. But now, instead of bringing the final volume up to 100ml, we keep adding water until the mass is 100g. This would give a precise 2.5% solution. In practice, the difference between making a 2.5% (by weight) solution and a 2.5% (w/v) is negligible. Even though most solids have a density which can differ from water by a factor of 10 or more, when they are disolved in water, the solute will rarely differ from water by more than a factor of 2. Sucrose (table sugar) is a notable exception. I don't know off-hand what its density is when it is dissolved, but it is significantly greater than 1g/ml. So let's say we have a solute which has a density of 2g/ml when it is in aqueous form and for which 10g takes up a volume of 3ml in aqueous form. Let's say we want a 10% solution. If we make our solution 10% (by weight), then we will end up with 100g solution that contains 10g of solute. If we make our solution 10% (w/v), then we will have 10g of solute in 100ml of solution. But the mass of our solution will be 105g. So, by weight, we have created a (10g/105g) 9.5% solution. If the density of the aqueous form of the solute were closer to 1g/ml, this error would be less. Moreover, the most important thing in chemistry and biochemistry is reproducibility, and (w/v) solutions are quite reproducible. Additionally, if you mix a 5% (w/v) solution of solute A with an equal volume of a 10% (w/v) solution of solute B, then you will end up with a solution which is 2.5% (w/v) for solute A and 5% (w/v) of solute B. (Solutions which are made strictly by weight also share this property.) So there is some error in (w/v) calcuations, but it is quite consistent error. The most precise way to talk about concentration is actually molarity, which is briefly discussed here: pH Value http://mathforum.org/library/drmath/view/56359.html But (w/v) is unambiguous as long as you specify that you are giving percentages as (w/v). Does that clear things up? - Doctor Achilles, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994- The Math Forum at NCTM. All rights reserved.
http://mathforum.org/dr.math/