Counting in Base 5Date: 03/02/2004 at 09:25:55 From: NaTasha Subject: I need help There are 5 counting numerals in base 5 (0 to 4). Count from 1 to 7 in base 5. I just don't understand to do it. Date: 03/02/2004 at 11:09:29 From: Doctor Peterson Subject: Re: I need help Hi, NaTasha. In base 5, you count by fives the way we count by tens in base ten. Here's how you count in base 10: o 1 oo 2 ooo 3 oooo 4 ooooo 5 oooooo 6 ooooooo 7 oooooooo 8 ooooooooo 9 [oooooooooo] 10 = 1 ten and 0 [oooooooooo] o 11 = 1 ten and 1 [oooooooooo] oo 12 = 1 ten and 2 Once you reach ten, you start counting groups of ten, with extra ones left over. In base 4, to use a different example, we group by 4's: o 1 oo 2 ooo 3 [oooo] 10 = 1 four and 0 (this is 4 in base ten) [oooo] o 11 = 1 four and 1 (this is 5 in base ten) [oooo] oo 12 = 1 four and 2 (this is 6 in base ten) [oooo] ooo 13 = 1 four and 3 (this is 7 in base ten) [oooo][oooo] 20 = 2 fours and 0 (this is 8 in base ten) [oooo][oooo] o 21 = 2 fours and 1 (this is 9 in base ten) So each time you have a new complete group of four, you add 1 to the "fours" place, and start over with 0 ones. We never have more than 3 in any place in the number, since if there were four or more we could package them up. Can you try the same thing with base 5? Here is a place to look for more help: Number bases http://mathforum.org/dr.math/faq/faq.bases.html If you have any further questions, feel free to write back. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2015 The Math Forum
http://mathforum.org/dr.math/