Associated Topics || Dr. Math Home || Search Dr. Math

### Two Planes and Not Enough Information

```Date: 08/10/2004 at 17:36:30
From: Crystal
Subject: Two Planes Leave Chicago

Two planes leave Chicago, one traveling due east and the other due
west.  The first travels 100 miles per hour faster than the second.
How long will it be until they are 2000 miles apart?

I figured out that if plane two is going at X mph, then plane one is
traveling at X + 100 mph.  But I can't figure out the value of x.

```

```
Date: 08/11/2004 at 10:20:45
From: Doctor Ian
Subject: Re: Two Planes Leave Chicago

Hi Crystal,

Let's think about a simpler problem for a moment:

Suppose you and I start at some point, standing back to
back, and I walk away from you at a speed of 10 feet
per second.  How long will it take until we're 40 feet
apart?

Now consider this twist on the problem:

Suppose you and I start at some point, standing back to
back, and walk away from each other at a speed of 5 feet
per second.  How long will it take until we're 40 feet
apart?

Do you see why these are really asking the same thing?  Since we're
concerned about the distance between us, we don't really care how fast
either of us is moving relative to the _ground_.  We just care how
fast we're moving relative to each other.

So I could make lots of variations on the problem:  I move at 8 feet
per second, and you move at 2 feet per second; I move at 4 feet per
second, and you move at 6 feet per second; and so on.  In fact, I
could make a version like this,

Suppose you and I start at some point.  I walk at a speed
of 12 feet per second, and you move at a speed of 2 feet
per second IN THE SAME DIRECTION.  How long will it take
until we're 40 feet apart?

and it's _still_ the same, because I'm still moving away from _you_ at
10 feet per second.  Does this make sense?

These problems are a classic application of

distance = rate * time

That is, it's the same as

At a speed of 10 feet per second, how long does it take to
move 40 feet?

We can write an equation

40 feet = 10 feet/sec * x seconds
40 = 10 * x
4 = x

Clearly after 4 seconds we will be 40 feet apart.

Having said all this, let's look at the original problem.  As you
said, if the first plane is traveling at speed x, then the second
travels at speed (x + 100).  This is the same as if one of the planes
stays on the ground, and the other moves away at a speed of
(x + x + 100).  So after h hours, the distance between the planes will be

distance = rate * time
2000 = (x + x + 100) * h

But there's a problem here!  It's not possible to find a unique
solution.  For example, I could say that x is 200 miles per hour.
Then the time is

2000 = (200 + 200 + 100) * h
2000 = 500 * h
4 = h  so it will take 4 hours.

On the other hand, I could say that v is 150 miles per hour:

2000 = (150 + 150 + 100) * h
2000 = 400 * h
5 = h  so now it will take 5 hours.

And there are infinitely many other solutions that will work.  What
the equation is telling you is that there is a relationship between
the value of x (the speed of the slower plane) and the value of h (the
amount of time required); but it's not enough information to specify a
_unique_ value for either quantity.

There are (at least) a couple of possibilities here.  One is that
there's more to the problem than you've said, and the extra
information would allow you to nail down a particular time.  Another
is that you're not really expected to come up with a unique value for
the time, i.e., you're supposed to end up with an equation that you
can use to determine the time that corresponds to any chosen value of
x.  To do that, you'd want to rearrange the equation

2000 = (x + x + 100) * h

to make it look like

h = [something involving only x's and numbers]

or anything else.

- Doctor Ian, The Math Forum
http://mathforum.org/dr.math/
```
Associated Topics:
Middle School Equations
Middle School Word Problems

Search the Dr. Math Library:

 Find items containing (put spaces between keywords):   Click only once for faster results: [ Choose "whole words" when searching for a word like age.] all keywords, in any order at least one, that exact phrase parts of words whole words

Submit your own question to Dr. Math
Math Forum Home || Math Library || Quick Reference || Math Forum Search