Linear ProgrammingDate: 10/15/2003 at 01:24:23 From: Sharleen Subject: optimization P and Q are ingredients with composition as shown below: Ingredient A (unit/g) B (unit/g) C (unit/g) ---------- ---------- ---------- ---------- P 2 1 5 Q 2 4 1 These ingredients are mixed with a filler ingredient weighing at least 85g to make batches with a total of 100g, pressed into one. Each batch contains at least 12 units of A, at least 12 units of B and at least 10 units of C. Unit costs are $2.00/g for P and $3.00/g for Q. How many grams of each per batch will minimize the production cost? Date: 10/15/2003 at 05:12:29 From: Doctor Luis Subject: Re: optimization Hi Sharleen, First, some definitions. Let the masses of ingredients P and Q be MP and MQ respectively. Let MF be the mass of the filler ingredient, and let UA, UB, and UC be the number of units of A, B, C present in a batch. Finally, let CP and CQ be the unit costs of ingredients P and Q. Then, we know from the problem that MF >= 85g MF + MP + MQ = 100g UA = 2*MP + 2*MQ >= 12 UB = 1*MP + 4*MQ >= 12 UC = 5*MP + 1*MQ >= 12 CP = $2.00/g CQ = $3.00/g We can simplify the first two by combining them into MF + MP + MQ >= 85 + MP + MQ 100 >= 85 + MP + MQ or MP + MQ <= 15 To get the net cost, we just multiply the unit (gram) cost of each ingredient by the mass of each ingredient. Unit cost C = CP*MP+CQ*MQ = 2MP + 3MQ To maximize C(MP,MQ) we look at the region bounded by the four inequalities MP + MQ <= 15 2MP + 2MQ >= 12 MP + 4MQ >= 12 5MP + MQ >= 12 Graphically, it's the shaded region, R, in the following graph: Since the slope of the cost function does not match the slope of any of the edges above, then the cost function achieves its minimum at one of the corners of the shaded region above. You can visualize how the lines of equal cost sweep through the region R if you look at the following animated gif: Can you tell which vertex of R has the least cost associated with it? Let us know if you have any more questions. - Doctor Luis, The Math Forum http://mathforum.org/dr.math/ |
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