|


Solving Equations with Fractions in ThemDate: 12/06/2004 at 15:12:14 From: Amanda Subject: How do you solve equations with multiplication I'm stuck on -5/7 n = 35. I don't understand how you change a fraction like this to a whole number.
Date: 12/06/2004 at 22:00:29
From: Doctor Boyd
Subject: Re: How do you solve equations with multiplication
Hi Amanda,
Thanks for writing to Dr. Math. Let's look at a similar but slightly
easier problem:
1
--- n = 35
7
We know that one seventh of "n" is 35, so now we need to collect
together enough pieces of "n" to make a whole "n".
Let's pretend that "n" is this long:
+----------------------------------+
Now, I can break it into 7 pieces:
+----+----+----+----+----+----+----+
And I know that each of these pieces is 35
35 35 35 35 35 35 35
+----+----+----+----+----+----+----+
So the total of "n" is
35 + 35 + 35 + 35 + 35 + 35 + 35 = 245
Now, notice that there are 7 of these, so it could be a multiplication:
7 * 35 = 245
So, if we look back at our original equation, we see that all we had
to do was take 7 "1/7 n"s and 7 "35"s to find out how much one "n" was
worth. In other words, we just multiply both sides by "7":
1
--- n = 35
7
1
7 * --- n = 7 * 35 -->(Multiply both sides by 7)
7
7
--- n = 7 * 35 -->( 7 * 1/7 = 7/7)
7
1 * n = 245 -->(7/7 = 1)
n = 245
Does that give you a clue of how to solve your question? Please write
back if you'd like some more help with this, or if you have any other
questions.
All the best,
- Doctor Boyd, The Math Forum
http://mathforum.org/dr.math/
|
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]


Ask Dr. MathTM
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/