How a Calculator Determines Values of Trig FunctionsDate: 03/19/2005 at 14:14:21 From: Adri Subject: Powerseries I'm interested in how my calculator finds the answer of sin(pi/4) or tan(pi/6). I think it uses power series to calculate the answer, but which ones? There are several power series for sin, cos, tan, etc. but which ones are being used by modern calculators (TI-83 for example)? Date: 03/19/2005 at 17:40:44 From: Doctor Tom Subject: Re: Powerseries I can't say for sure exactly what's done in your calculator, but I know how such things are usually computed. For something like sine, where the function is periodic, you really just need to compute sines of angles between, say, 0 and 90 degrees. What's done is to find a polynomial that approximates the sine curve "as well as possible" over that interval. "As well as possible" may have different meanings, but a common one might be the polynomial with the smallest absolute error over the entire range. As you consider polynomials of fixed degree, say 6, there is one that is the best fit. If you go to eighth degree polynomials, you can do better, and so on. Your calculator has a certain precision that it needs to obtain, so the designers find the polynomial of least degree that gives the required accuracy. Many books on numerical methods or computer arithmetic list the coefficients for various functions and various degree polynomial approximants. Other functions, like square-root, are done differently. They do the exponent part and the mantissa part separately. They work in base 2, so suppose you want to take the square root of: 111010.0110101 (in binary) Shift the binary point to the left to get a number between 1 and 4: 11.10100110101 x 2^4 that has an even exponent. Then the square root will be the square root of the number on the left times 2^2. To take the square root of a number between 1 and 4, just have a small table of exact square roots for, say, 128 equally-spaced values. Find the closest one in the table and use it as a first guess. Then use Newton's method an appropriate number of times to obtain the desired accuracy. Newton's method roughly doubles the accuracy of your current guess with every iteration. In other words, the number of accurate decimal (or binary) points doubles with each step. So if you need 64 bit accuracy, and your table's initial guess gives 5 bits, then you get 10, 20, 40 and 80 bits with 1, 2, 3 and 4 iterations. A larger table reduces the number of iterations, but chews up more memory, so there's a trade-off for the calculator designers. Other functions are computed with combinations of these ideas. - Doctor Tom, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/