Comparing Running RatesDate: 01/20/2005 at 18:50:05 From: Michael Subject: The race... Jack and Jane ran the 100 yard dash. When Jane won, Jack was 10 yards behind her. In the next race, Jane started 10 yards behind the starting line, and both Jane and Jack ran at the same rate as before. Who won? Reasoning tells me the second race should be a tie, but the book says it isn't. Why? What would it take to run a tie race? Date: 01/20/2005 at 19:59:36 From: Doctor Jeremiah Subject: Re: The race... Hi Michael, While Jane runs 100 yards, Jack only runs 90. So Jack can only run 9 yards for every 10 that Jane runs. If Jane is made to run 10 more yards (total of 110 yards) then Jack will run an extra 9 yards (total of 99 yards), so when Jane finishes the race the second time Jack will have only gone 99 yards. He only loses by a yard instead of 10 yards this time, but he still loses. In general, Jack only covers 90% of the distance Jane does. So in the second race Jane runs 110 yards and Jack covers 90% of that which is 99 yards. For it to be a tie, 90% of Jane's distance must equal 100 yards. Let's represent Jane's distance as "d" and do some calculations: 90% of d = 100 90/100 * d = 100 d = 100 divided by 90/100 d = 100 * (100/90) = 10000/90 = 111 and 10/90 yards. So if Jane is made to run 111 and 1/9 yards while Jack runs 100, it will be a tie. If she has to run more than 111 and 1/9 while he runs 100, she will lose. - Doctor Jeremiah, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/