Challenging Age Problem with System of EquationsDate: 01/30/2005 at 18:19:27 From: Sean Subject: insane two variable equation A man is three times as old as his son was at the time when the father was twice as old as his son will be two years from now. Find the present age of each if they sum to 55. It just involves too many clauses - I can't make sense of it! Date: 01/31/2005 at 12:09:51 From: Doctor George Subject: Re: insane two variable equat Hi Sean, Thanks for writing to Doctor Math. It may be easiest to think of this problem as having 3 variables. Here are the variables. F = Father's age today S = Son's age today n = some number of years ago Now we need three equations. We get them by translating each main idea from English into algebra. 1. A man is three times as old as his son was n years ago. F = 3(S - n) 2. n years ago the father was twice as old as his son will be two years from now. F - n = 2(S + 2) 3. The sum of their ages is 55. F + S = 55 Can you take it from here? Write again if you need more help. - Doctor George, The Math Forum http://mathforum.org/dr.math/ |
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