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Modeling Multiplying Two Negatives with Number LinesDate: 11/13/2006 at 07:36:28 From: Joan Subject: -2*-3= 6??? I'm trying to use a number line to figure out why -2 times -3 makes 6, and I can't do it. If I start at -2 and move to the right three times I wind up at 4, and if I move to the left I wind up at -8. What is the logic behind the rule of a negative times a negative makes a positive, and how do I demonstrate it on a number line?
Date: 11/13/2006 at 08:28:45
From: Doctor Rick
Subject: Re: -2*-3= 6???
Hi, Joan.
You can find a variety of ways to think about multiplication of
negatives, and also ways to *prove*, more or less formally, that a
negative times a negative is positive, in the Dr. Math FAQ:
Negative X Negative = Positive
http://mathforum.org/dr.math/faq/faq.negxneg.html
It's hard to demonstrate signed multiplication on a number line, but
there is a way to do it using *two* number lines. See what you think
of this:
Draw two number lines that cross at the origin on both lines--the
angle between the lines doesn't matter. To multiply a number x by
another number y, first draw a line through 1 on the first line and
x on the second line:
/
/
/
/
/
x /
*
/
/
/
---0--*-----------
/ 1
/
/
I can't draw that line, you'll have to do it on paper. Then draw
another line, parallel to this one and passing through the number y
on the first number line.
/
z /
*
/
/
x /
*
/
/
/
---0--*--*--------
/ 1 y
/
/
You can easily prove by similar triangles that
x/1 = z/y
so that
z = xy
That is, the position of z on the second number line is the product
of x and y.
Now, use this same graphical method to multiply -2 by -3:
/
*-2*-3=6
/
/
/
/
/
/
/
/
/
/
/
/
--+------------0----+-------------
-3 / 1
/
/
*-2
/
/
Draw a line connecting 1 on the first (horizontal) number line with -2
on the second number line. Draw a line parallel to this line, and
passing through -3 on the first number line. You will see that it
intersects the second number line at 6, which is therefore the product
of -2 and -3.
- Doctor Rick, The Math Forum
http://mathforum.org/dr.math/
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