Finding the Center of Two Points in Latitude/Longitude FormDate: 08/11/2006 at 07:02:46 From: Sam Subject: Center Of Two Latitude Points Hi, How can I calculate the center (expressed as a latitude value) of two latitude points? I want to find the center of a rectangle expressed in longitude and latitude. The rectangle is defined by the upper left and bottom right corners (both represented as lat/lon locations). Basically I need to find the midpoint or center between these two points. The reason I want to find the center is so that I can divide the area into four smaller sub-areas. Each new sub-area can be defined using one of the original corners and the center (if we are going to define it using two locations). I know the four sub-areas won't be equal because of the convergence of latitude lines, but that's ok. I want to be able to divide the Earth up like this in order to perform efficient proximity searches. Being able to place a location within an area of the Earth means only other locations within that area and certain surrounding areas need to have Haversine applied to find their distance and is therefore much less computationally heavy. The ability to start off with large areas and then divide them into smaller areas is needed so that a larger area can be queried when a surrounding location is sparsely populated. The areas are divided and re-populated whenever one becomes occupied with a certain amount of locations. I plan to start by dividing the Earth into four equal areas. This time they will be equal as it's simple to do this with a sphere and latitude/longitude, but I'm not sure where to go from there. Any help would be greatly appreciated. Thanks a lot. Date: 08/11/2006 at 13:33:40 From: Doctor Rick Subject: Re: Center Of Two Latitude Points Hi Sam, Here are two exchanges in the Dr. Math Archive concerning the related concept of a "spherical rectangle". These pages won't answer your question, but will give you some background information: Spherical "Rectangles" http://mathforum.org/library/drmath/view/60748.html Area of a Latitude-Longitude Rectangle http://mathforum.org/library/drmath/view/63767.html You are interested in "latitude-longitude rectangles"; they don't have to be squares (equal sides). I don't think you need a lot of precision, but dividing the LLrectangle into four LLrectangles of equal area will fit your need well. Going to the last page I referred you to, I get the formula A = (pi/180)R^2 |sin(lat1)-sin(lat2)| |lon1-lon2| where R is the radius of the earth (which won't matter to us since we're working with ratios), lat1 and lat2 are the latitudes of the top and bottom of the LLrectangle, and lon1 and lon2 are the longitudes of the sides. The longitude of the vertical dividing line is easy ... well, almost. We can just take the average of lon1 and lon2, *unless* the LLrectangle spans longitude 180 (assuming you're working with longitudes from -180 to +180). We can recognize that case because the difference |lon2-lon1| will be greater than 180 degrees. The algorithm for the dividing longitude is lon = (lon1+lon2)/2 if |lon2-lon1| > 180 then if lon > 0 then lon = lon - 180 else lon = lon + 180 or equivalent. If you have set things up so that no LLrectangle will cross over longitude 180, you only need the first line. To find the latitude of the horizontal dividing line, we look for lat such that the area from lat1 to lat equals the area from lat to lat2: (pi/180)R^2 |sin(lat1)-sin(lat)| |lon1-lon2| = (pi/180)R^2 |sin(lat)-sin(lat2)| |lon1-lon2| which can be simplified to |sin(lat1)-sin(lat)| = |sin(lat)-sin(lat2)| If we can assume that lat1 and lat2 are in the same hemisphere (both positive or both negative), then lat will obviously have the same sign, and we can simplify to sin(lat1)-sin(lat) = sin(lat)-sin(lat2) sin(lat1) + sin(lat2) = 2sin(lat) lat = arcsin((sin(lat1) + sin(lat2))/2) My instinct is to divide the earth into eight octants to start with; this will result in regions that are more "square" in some sense. First divide the earth into positive and negative longitudes (thus simplifying the lon calculation), then start applying the divide- into-four-regions algorithm to divide each hemisphere. (The latitude division formula will work in this case even though lat1 and lat2 have different signs.) - Doctor Rick, The Math Forum http://mathforum.org/dr.math/ Date: 08/12/2006 at 11:58:35 From: Sam Subject: Thank you (Center Of Two Latitude Points) Thank you so much for the help with this problem. As you suggested I did plan to make the original divisions at longitude 180. I will also make eight original divisions as you suggested. Thanks again for your help, I was amazed at the speed of your response and the effort you put in. -Sam |
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