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Introduction to Algebraic FractionsDate: 05/29/2008 at 06:45:49 From: Autumn Subject: Algebraic fractions and its problems. What are algebraic fractions? My teacher explained this in school but I still do not understand what algebraic fractions are. Can you help me?
Date: 05/29/2008 at 08:48:35
From: Doctor Ian
Subject: Re: Algebraic fractions and its problems.
Hi Autumn,
A fraction is just a division we haven't done yet. So, for example,
3/4 means "3 divided by 4, whatever that would be".
If we have algebraic expressions in place of constants, like
x/3
or
(x^2 - 4)/(x + 2)
then we have an "algebraic fraction".
But that's not a big deal. They're just like any other fractions,
i.e., they follow the same rules. For example, if we have a fraction
like 6/15, we can reduce it by identifying common factors in the
numerator and denominator:
6 3 * 2 2
-- = ----- = - because the 3's cancel
15 3 * 5 5
Does that look familiar? We can do the same thing with a fraction like
6x^3 3 * 2 * x * x * x 2x
----- = ----------------- = --
15x^2 3 * 5 * x * x 5
There's only one important difference here. Recall that we can't
divide by zero. That's not a problem with a fraction like 6/15, where
we know all the values... but with a fraction like (6x^3)/(15x^2), we
have to keep track of the fact that x can't ever be equal to zero.
Even if the simplified form (2x)/5 would allow that, the original form
wouldn't.
With quadratic and higher polynomials, we can get these kinds of
cancellations by factoring them into products of binomials, e.g.,
x^2 - 4 (x + 2)(x - 2) x - 2
------------ = -------------- = -----
x^2 + 5x + 6 (x + 2)(x + 3) x + 3
Again, we need to keep in mind that BOTH -2 and -3 are prohibited
values for x in the original expression.
Does this make sense?
- Doctor Ian, The Math Forum
http://mathforum.org/dr.math/
Date: 05/29/2008 at 09:48:11 From: Autumn Subject: Thank you (Algebraic fractions and its problems.) Thank you for that. It really did help and i can manage my homework better! Thanks again. |
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