Law of cosines

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(Example Triangulation)
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[[Image:SAS triangle.jpg]]
[[Image:SAS triangle.jpg]]
To find the side length <math>c</math>,
To find the side length <math>c</math>,

Revision as of 10:04, 30 May 2011

The law of cosines is a formula that helps in triangulation when two or three side lengths of a triangle are known. The formula relates all three side lengths of a triangle to the cosine of a particular angle.

 c^{2} = a^{2} + b^{2} - 2ab \cos C

When to use it: SAS, SSS.



Let  \vartriangle ABC be oriented so that  C is at the origin, and  B is at the point (a,0).


Distance Formula

 distance = \sqrt {(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}

c is the distance from  A to  B.

Substituting the appropriate points into the distance formula gives us

 c = \sqrt {(a-b \cos C)^{2} + (0-b \sin C)^{2}}

Squaring the inner terms, we have

 c = \sqrt {(a^{2}-2ab \cos C+b^{2} \cos^{2} C) + (b^{2} \sin^{2} C)}

Since  \cos^{2} C +  \sin^{2} C = 1,

 c = \sqrt {(a^{2}+b^{2}-2ab \cos C+b^{2}}

Square both sides for

 c^{2} = (a^{2}+b^{2}-2ab \cos C+b^{2}

Example Triangulation

Complete the triangle using the law of cosines.

 c^{2} = a^{2} + b^{2} - 2ab \cos C

Image:SAS triangle.jpg


To find the side length c,

 c^{2} = 6^{2} + (6 \sqrt{2})^{2} -2 (6) (6 \sqrt{2}) \cos 45^\circ

Simplify for

 c^{2} =36 + 36 (2) - 72 \sqrt{2}) \cos 45^\circ

Since  \cos 45^\circ = \frac{1}{\sqrt{2}}, substitution gives us

 c^{2} =36 + 36 (2) - 72 \sqrt{2} (\frac{1}{\sqrt{2}})

Simplify for

 c^{2} =36 + 72 - 72

 c^{2} =36

Taking the square root of both sides gives us

 c =6

Now we can orient the triangle differently to get get a new version of the law of cosines so we can find angle measure B,

 b^{2} = a^{2} + c^{2} - 2ab \cos B

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